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AlladinOne [14]
4 years ago
11

3. In a first­ order reaction, what is the rate constant if the rate is 0.060M/s and the reactant concentration is 0.030M?

Chemistry
1 answer:
Scilla [17]4 years ago
6 0
The rate law for a first order reaction is:
rate = k x [A]
where k is the rate constant and [A] is the concentration of the reactant A. The rate of a first order reaction depends only on concentration of one reactant.

Here, rate = 0.060 M/s and [A] = 0.030 M.
From the first equation, we can write:
k = rate / [A]
k = 0.060 M/s / 0.030 M = 2 s^-1
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Answer:

The new volume will be 367mL

Explanation:

Using PV = nRT

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n1 = 0.552moles

At constant temperature and pressure, the value is

P * 0.000259 = 0.552 * RT ------equation 1

= 0.552 / 0.000259

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V2 = ?

n2 = 0.552 + 0.232

n2 = 0.784mole

Using ideal gas equation,

PV = nRT

P * V2 = 0.784 * RT ---------- equation 2

Combining equations 1 and 2 we have;

V2 = 0.784 / 2131.274

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<h3>Answer:</h3>

5.6 Liters

<h3>Explanation:</h3>
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We need to know that;

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