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4 years ago

What is true of a compound?

Chemistry

2 answers:

zalisa [80]4 years ago

7 0

Answer:

It does not always retain the properties of the substances that make it up

Explanation:

oksian1 [2.3K]4 years ago

6 0

Answer:

A/1

Explanation:

Compounds do <em>NOT</em> always retain the properties of the substances that make it up.

You might be interested in

Which of the following notations is the correct noble gas configuration for Li

Anettt [7]

Noble gas configuration for Li : [He]2s¹

<h3>Further explanation </h3>

In an atom, there are levels of energy in the shell and sub-shell

This energy level is expressed in the form of electron configurations.

Lithium with atomic number 3, then the electron configuration:

1s²2s¹

And for noble gas configuration or it can be called Condensed electron configurations :

[He]2s¹

8 0

3 years ago

Read 2 more answers

Choose the correct statements from the list below:

ioda

In chemistry:
When something is oxidized, it loses electrons.
When something is reduced, it gains electrons.
So the correct statements would be the second to last and third to last statements

6 0

3 years ago

Air is compressed from an inlet condition of 100 kPa, 300 K to an exit pressure of 1000 kPa by an internally reversible compress

ElenaW [278]

Answer:

(a) $W_{isoentropic}=8.125\frac{kJ}{mol}$

(b) $W_{polytropic}=7.579\frac{kJ}{mol}$

Explanation:

Hello,

(a) In this case, since entropy remains unchanged, the constant $k$ should be computed for air as an ideal gas by:

$\frac{R}{Cp_{air}}=1-\frac{1}{k} \\\\\frac{8.314}{29.11} =1-\frac{1}{k}\\$

$0.2856=1-\frac{1}{k}\\\\k=1.4$

Next, we compute the final temperature:

$T_2=T_1(\frac{p_2}{p_1} )^{1-1/k}=300K(\frac{1000kPa}{100kPa} )^{1-1/1.4}=579.21K$

Thus, the work is computed by:

$W_{isoentropic}=\frac{kR(T_2-T_1)}{k-1} =\frac{1.4*8.314\frac{J}{mol*K}(579.21K-300K)}{1.4-1}\\\\W_{isoentropic}=8.125\frac{kJ}{mol}$

(b) In this case, since $n$ is given, we compute the final temperature as well:

$T_2=T_1(\frac{p_2}{p_1} )^{1-1/n}=300K(\frac{1000kPa}{100kPa} )^{1-1/1.3}=510.38K$

And the isentropic work:

$W_{polytropic}=\frac{nR(T_2-T_1)}{n-1} =\frac{1.3*8.314\frac{J}{mol*K}(510.38-300K)}{1.3-1}\\\\W_{polytropic}=7.579\frac{kJ}{mol}$

$W_{isothermal}=RTln(\frac{p_2}{p_1} )=8.314\frac{J}{mol*K}*300K*ln(\frac{1000kPa}{100kPa} ) \\\\W_{isothermal}=5.743\frac{kJ}{mol}$

Regards.

8 0

3 years ago

You wish to construct a buffer of pH=7.0. Which of the following weak acids (w/ corresponding conjugate base) would you select?

Alex17521 [72]

Answer:

C.) HOCl Ka=3.5x10^-8

Explanation:

In order to a construct a buffer of pH= 7.0 we need to find the pKa values of all the acids given below

we Know that

pKa= -log(Ka)

therefore

A) pKa of HClO2 = -log(1.2 x 10^-2)

=1.9208

B) similarly PKa of HF= -log(7.2 x 1 0^-4)= 2.7644

C) pKa of HOCl= -log(3.5 x 1 0^-8)= 7.45

D) pKa of HCN = -log(4 x 1 0^-10)= 9.3979

If we consider the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution

The weak acid for making the buffer must have a pKa value near to the desired pH of the weak acid.

So, near to value, pH=7.0. , the only option is HOCl whose pKa value is 7.45.

Hence, HOCl will be chosen for buffer construction.

3 0

3 years ago

Pairs

BabaBlast [244]

Atoms are made up of protons, neutrons, and electrons.

Energy can be neither created nor destroyed.

Water freezes at 0°C

If a piece of platinum is placed in acid, it will not react.

<h3>What are the correct pairing of the given terms?</h3>

The correct pairing of the given terms are obtained from the given options as follows:

Atoms of elements contains three sub-atomic particles which are protons, neutrons, and electrons.

Energy is the ability to do work.

According to the law of conservation of energy, Energy can be neither created nor destroyed.

Water is a liquid which freezes at 0°C.

Therefore, Water freezes at 0°C.

Platinum is a metal which is less reactive than hydrogen, Hence, it cannot displace hydrogen from acids.

Hence, if a piece of platinum is placed in acid, it will not react.

In conclusion, the correct pairing gives the correct description of the properties of the given terms.

Learn more about atoms at: brainly.com/question/17545314

#SPJ1

3 0

2 years ago