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kozerog [31]
3 years ago
6

What is true of a compound?

Chemistry
2 answers:
zalisa [80]3 years ago
7 0

Answer:

It does not always retain the properties of the substances that make it up

Explanation:

oksian1 [2.3K]3 years ago
6 0

Answer:

A/1

Explanation:

Compounds do <em>NOT</em> always retain the properties of the substances that make it up.

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If a plant produces 9.31 mol of C6H12O6, how many moles of H2O are needed?
Mashutka [201]

The complete balanced chemical equation for photosynthesis in plants is:

6CO₂ + 6H₂O ----> C₆H₁₂O₆ + 6O₂

Based on the balanced equation the molar ratio between H₂O and C₆H₁₂O₆ is 6:1

This means that 6 moles of H₂O is need for every 1 mole of C₆H₁₂O₆

9.31 mol of C₆H₁₂O₆ x (6 moles of H₂O / 1 mole of C₆H₁₂O₆) = 55.86 moles of H₂O

Thus the moles of H₂O need is 55.86 .


5 0
3 years ago
Read 2 more answers
This lab question is: How can you distinguish a physical change from a chemical change?
geniusboy [140]

Answer:b,and c

Explanation:

4 0
2 years ago
Consider the electron configuration. mc011-1.jpg mc011-2.jpg mc011-3.jpgmc011-4.jpgmc011-5.jpg mc011-6.jpg mc011-7.jpgmc011-8.jp
zepelin [54]
The element which has the electronic configuration is CHLORINE.
The atomic number of chlorine is 17 and it has 7 valence electrons in its outermost shell. Because it needs only one more electrons to have a stable octet, it usually react with metals from group one of the periodic table who are normally willing to donate the single electrons in their outermost shells. The ground state electronic configuration of chlorine atom is 1S^2 2S^2 2P^6 3S^2 3P^5.
5 0
2 years ago
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Calculate the standard enthalpy of formation of NOCl(g) at 25 ºC, knowing that the standard enthalpy of formation of NO(g) at th
stepan [7]

Answer:

The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol

Explanation:

The ∆H (heat of reaction) of the combustion reaction is the heat that accompanies the entire reaction. For its calculation you must make the total sum of all the heats of the products and of the reagents affected by their stoichiometric coefficient (number of molecules of each compound that participates in the reaction) and finally subtract them:

Enthalpy of the reaction= ΔH = ∑Hproducts - ∑Hreactants

In this case, you have:  2 NOCl(g) → 2 NO(g) + Cl₂(g)

So, ΔH=2*H_{NO} +H_{Cl_{2} }-2*H_{NOCl}

Knowing:

  • ΔH= 75.5 kJ/mol
  • H_{NO}= 90.25 kJ/mol
  • H_{Cl_{2} }= 0 (For the formation of one mole of a pure element the heat of formation is 0, in this caseyou have as a pure compound  the chlorine Cl₂)
  • H_{NOCl}=?

Replacing:

75.5 kJ/mol=2* 90.25 kJ/mol + 0 - H_{NOCl}

Solving

-H_{NOCl}=75.5 kJ/mol - 2*90.25 kJ/mol

-H_{NOCl}=-105 kJ/mol

H_{NOCl}=105 kJ/mol

<u><em>The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol</em></u>

8 0
2 years ago
The electron configuration 1sÆ 2sÆ2pÒ 3sÆ3pÒ represents which noble gas?
ch4aika [34]
This noble gas is argon (Ar), because its third energy level is full.
4 0
2 years ago
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