Answer:
1.27 atm is the final pressure of the oxygen in the flask (with the stopcock closed).
2.6592 grams of oxygen remain in the flask.
Explanation:
Volume of the flask remains constant = V = 2.0 L
Initial pressure of the oxygen gas = 
Initial temperature of the oxygen gas = 
Final pressure of the oxygen gas = 
Final temperature of the oxygen gas = 
Using Gay Lussac's law:
1.27 atm is the final pressure of the oxygen in the flask (with the stopcock closed).
Moles of oxygen gas = n
(ideal gas equation)
Mass of 0.08310 moles of oxygen gas:
0.08310 mol × 32 g/mol = 2.6592 g
2.6592 grams of oxygen remain in the flask.
Answer:
12.34 amu
Explanation:
Let the 1st isotope be A
Let the 2nd isotope be B
Let the 3rd isotope be C
From the question given above, the following data were obtained:
1st Isotope (A):
Mass of A = 12.32 amu
Abundance (A%) = 19.5%
2nd isotope (B):
Mass of B = 13.08 amu
Abundance (B%) = 26.23%
3rd isotope (C):
Mass of C = 11.99 amu
Abundance (C%) = 54.27%
Atomic mass of X =?
The atomic mass of the element X can be obtained as follow:
Atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] + [(Mass of C × C%)/100]
= [(12.32 × 19.5)/100] + [(13.08 × 26.23)/100] + [(11.99 × 54.27)/100]
= 2.402 + 3.431 + 6.507
= 12.34 amu
Thus, the atomic mass of the element X is 12.34 amu
Answer:
it depends on how you use action Because action means you are doing something and maybe action like reaction or something like a feeling if a bomb occurs that is the action.
Explanation:
(1). It is known that in a reaction equation, reactants are placed or written on left hand side and products are written on the right hand side.
For example, 
Hence, in a reaction equation you start with the reactants and end up with the products.
(2). The number of atoms in a reaction will remain the same because according to the law of conservation of mass, mass of reactants will be equal to the mass of products.
Therefore, number of atoms on the reactant side will be equal to the number of atoms on product side.
