The molarity of the acid sample H₂SO₄ is 0.052M .
<h3>What is Molarity ?</h3>
Molarity (M) is the amount of a substance in a certain volume of solution.
Molarity is defined as the moles of a solute per liters of a solution.
Molarity is also known as the molar concentration of a solution
Now to determine the molarity of the acid sample
V( H₂SO₄) = 24.0 mL in liters = 24.0 / 1000 = 0.024 L
M(H₂SO₄) = ?
V(NaOH) = 20.0 mL = 20.0 / 1000 = 0.02 L
M(NaOH) = 0.125 M
Number of moles NaOH :
n = M x V
n = 0.125 x 0.02
n = 0.0025 moles of NaOH
H₂SO₄(aq) + 2 NaOH(aq) = Na₂SO₄(aq) + 2 H₂O(l)
1 mole H₂SO₄ ---------- 2 mole NaOH
? mole H₂SO₄ ---------- 0.0025 moles NaOH
moles = 0.0025 * 1 / 2
= 0.00125 moles of H₂SO₄
M(H₂SO₄) = n / V
M = 0.00125 / 0.024
= 0.052 M
Therefore the molarity of the acid sample H₂SO₄ is 0.052M .
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<span>Answer:
Enthalpy is delta-H-
We need to look at the molecule and determine which bonds are broken adn which bonds are formed.
Bonds that are broken are H-H (from the H2 molecule) and the C=O from acetone.
their energies add up like this: 436 kJ + 745 kJ = 1181 kJ
looking at the bonds formed, these are C-O, O-H, and C-H. these add up to 1229 kJ
solving for delta H by taking the sum of the broken bonds and subtracting the sum of the formed bonds, like so:
1181 - 1229 = -48 kJ</span>
Answer:
P₂ = 5000 KPa
Explanation:
Given data:
Initial volume = 2.00 L
Initial pressure = 50.0 KPa
Final volume = 20.0 mL (20/1000=0.02 L)
Final pressure = ?
Solution:
The given problem will be solved through the Boly's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
50.0 KPa × 2.00L = P₂ × 0.02 L
P₂ = 100 KPa. L/0.02 L
P₂ = 5000 KPa
Compound name:
- Chlorine monofluoride
Formula: ClF
