Answer:
0.266 m
Explanation:
Assuming the lump of patty is 3 Kg then applying the principal of conservation of linear momentum,
P= mv where p is momentum, m is mass and v is the speed of an object. In this case
where sunscripts p and b represent putty and block respectively, c is common velocity.
Substituting the given values then
3*8=v(15+3)
V=24/18=1.33 m/s
The resultant kinetic energy is transferred to spring hence we apply the law of conservation of energy
where k is spring constant and x is the compression of spring. Substituting the given values then

To solve this problem we will apply the concepts related to pressure, depending on the product between the density of the fluid, the gravity and the depth / height at which it is located.
For mercury, density, gravity and height are defined as



For the air the defined properties would be



We have for equilibrium that


Replacing,

Rearranging to find 


Therefore the elevation of the mountain top is 9400ft
Revolution means orbiting around another body.
<span>A year is the time for a planet to complete one orbit around the Sun. 100% sure
</span>
Answer:
0.02 s
160 m/s
Explanation:
Given:
Δx = 1.6 m
v₀ = 0 m/s
a = 8000 m/s²
A) Find t.
Δx = v₀ t + ½ at²
1.6 m = (0 m/s) t + ½ (8000 m/s²) t²
t = 0.02 s
B) Find v.
v² = v₀² + 2aΔx
v² = (0 m/s)² + 2 (8000 m/s²) (1.6 m)
v = 160 m/s