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Alina [70]
3 years ago
7

What is relation of acceleration of a body to its mass and applied force​

Physics
1 answer:
irinina [24]3 years ago
3 0
The law states that external forces cause objects to accelerate, and the amount of acceleration is directly proportional to the net force and inversely proportional to the mass of the object.


If you can’t copy and paste it just reword it
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All are examples of electric forces except _________. A. a neutron pushing on another neutron B. an electron pushing on a proton
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A) a neutron pushing on another neutron.

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A 45.0 kg girl is standing on a 159 kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat,
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(a) v_g_i=1.08\frac{m}{s}

(b) v_p_i=-0.3\frac{m}{s}

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\Delta p=0\\p_i=p_f

Initially, the girl and the plank are at rest. So, relative to the ice, we have:

0=m_gv_g_i+m_pv_p_i\\v_p_i=-\frac{m_gv_g_i}{m_p_i}(1)

(a) The velocity of the girl relative to the ice is:

v_g_i=v_g_p+v_p_i(2)

Here, v_g_p is the velocity of the girl relative to the plank and v_p_i is the velocity of the plank relative to the ice.

Replacing (1) in (2):

v_g_i=v_g_p-\frac{m_gv_g_i}{m_p_i}\\v_g_i+\frac{m_gv_g_i}{m_p_i}=v_g_p\\v_g_i(1+\frac{m_g}{m_p})=v_g_p\\v_g_i=\frac{v_g_p}{1+\frac{m_g}{m_p}}\\v_g_i=\frac{1.38\frac{m}{s}}{1+\frac{45kg}{159kg}}\\v_g_i=1.08\frac{m}{s}

(b) According to (2), the velocity of the plank relative to the surface of ice is:

v_p_i=v_g_i-v_g_p\\v_p_i=1.08\frac{m}{s}-1.38\frac{m}{s}\\v_p_i=-0.3\frac{m}{s}

The negative sing indicates that the plank is moving to the left.

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