1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Serhud [2]
2 years ago
15

Plane-polarized light is incident on a single polarizing disk with the direction of E0 parallel to the direction of the transmis

sion axis. Through what angle should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of:
Physics
1 answer:
DENIUS [597]2 years ago
6 0

Answer: Plane-polarized light is incident on a single polarizing disk with the direction of E0 parallel to the direction of the transmission axis. Through angle \alpha=cos^-1(\sqrt{\frac{1}{n} }) should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of n .

Explanation: To find the correct answer, we need more clarifications about the Malu's law.

<h3>What is Malu's law?</h3>
  • When a beam of plane polarized light is passed through an analyzer, the intensity I of the transmitted light varies directly as the square of the angle between the direction of polarizer and the analyzer.

                                 I=I_0cos^2\alpha

where, I_0 is the maximum intensity of transmitted light.

  • Intensity of the light transmitted through the polarizer is half of the incident intensity.
<h3>How to solve the problem?</h3>
  • Here in the question ,let's take the factor at which the intensity of transmitted light is reduced by as n.
  • we have the expression

                                            I=I_0cos^2\alpha

  • we have to find the value of angle alpha, so that the intensity in the transmitted beam is reduced by a factor of n.

                                 \alpha =cos^-1\sqrt{(\frac{I}{I_0}} )=cos^-1\sqrt{\frac{I}{nI} } \\\alpha =cos^-1\sqrt{\frac{1}{n} }

  • If we know the value of n, then we can easily find the angle.

Thus, we can conclude that, the value of angle alpha, so that the intensity in the transmitted beam is reduced by a factor of n will be,

                                 \alpha=cos^-1(\sqrt{\frac{1}{n} }) .

Learn more about Malu's law here: brainly.com/question/28045350

#SPJ4

You might be interested in
A 10.0-g bullet moving at 300 m/s is fired into a 1.00-kg block at rest. the bullet emerges (the bullet does not get embedded in
sesenic [268]
Momentum before the hit:
p = mv = 0.01 * 300 + 1 * 0 

Momentum after the hit:
p = 0.01 * 150 + 1 * v

Momentum is conserved:
0.01 * 300 = 0.01 * 150 + v 
3 = 1.5 + v
v = 1.5

The velocity of the block after the collision is 1.5 m/s.
7 0
4 years ago
Two power lines run parallel for a distance of 222 m and are separated by a distance of 40.0 cm. if the current in each of the t
earnstyle [38]
1) Magnitude of the force:

The magnetic field generated by a current-carrying wire is
B= \frac{\mu_0I}{2 \pi r}
where
\mu_0 is the vacuum permeability
I is the current in the wire
r is the distance at which the field is calculated

Using I=135 A, the current flowing in each wire, we can calculate the magnetic field generated by each wire at distance 
r=40.0 cm=0.40 m, 
which is the distance at which the other wire is located:
B= \frac{\mu_0 I}{2 \pi r}= \frac{(4 \pi \cdot 10^{-7} N/A^2)(135 A) }{2 \pi (0.40 m)}=6.75 \cdot 10^{-5} T

Then we can calculate the magnitude of the force exerted on each wire by this magnetic field, which is given by:
F=ILB=(135 A)(222 m)(6.75 \cdot 10^{-5}T)=2.03 N

2) direction of the force: 
The two currents run in opposite direction: this means that the force between them is repulsive. This can be determined by using the right hand rule. Let's apply it to one of the two wires, assuming they are in the horizontal plane, and assuming that the current in the wire on the right is directed northwards:
- the magnetic field produced by the wire on the left at the location of the wire on the right is directed upward (the thumb of the right hand is directed as the current, due south, and the other fingers give the direction of the magnetic field, upward)

Now let's apply the right-hand rule to the wire on the right:
- index finger: current --> northward
- middle finger: magnetic field --> upward
- thumb: force --> due east --> so the force is repulsive

A similar procedure can be used on the wire on the left, finding that the force exerted on it is directed westwards, so the force between the two wires is repulsive.
6 0
3 years ago
You are trying to find out how high you have to pitch a water balloon in order for it to burst when it hits the ground. You disc
FrozenT [24]

Answer:

The balloon hit the ground with velocity -15.34 m/s

Explanation:

<em>Lets explain how to solve the problem</em>

You found that the best height to pitch a water balloon in order for it to

burst when it hits the ground is 12 meters.

We consider that the 12 meters is the maximum height, so the velocity

at this height is zero.

To find the velocity when the balloon hits the ground lets use the rule

<em>v² = u² + 2gh</em>, where v is the final velocity, u is the initial velocity, g is

the acceleration of gravity and h is the height.

u = 0 , h = 12 m , g = 9.8 m/s²

<em>Substitute these values in the equation above</em>

v² = 0 + 2(9.8)(12)

v² = 235.2

<em>Take square root for both sides</em>

v = ± \sqrt{235.2}

The velocity is downward, then it's a negative value

Then v = -15.34 m/s

<em>The balloon hit the ground with velocity -15.34 m/s</em>

6 0
3 years ago
Starting from rest, a 6.79 kg block slides 2.82 m down a rough 20.7 ◦ incline. The coefficient of kinetic friction between the b
Veronika [31]

Answer:

23.52092 J

Explanation:

m = Mass of block = 6.79 kg

s = Sliding distance = 2.82 m

\theta = Angle of slide = 20.7°

\mu = Coefficient of kinetic friction = 0.425

g = Acceleration due to gravity = 9.8 m/s²

Work done by the force of gravity is given by

W=mgsin\theta\\\Rightarrow W=6.79\times 9.8\times sin20.7\\\Rightarrow W=23.52092\ J

The work done by the force of gravity is 23.52092 J

8 0
3 years ago
There is an electric field in the region between the two plates. The magnitude of this electric field is ed. This imposes anothe
krok68 [10]

Answer:

it is essential that the charge on the plates are of the same magnitude, but in the opposite direction

Explanation:

The configuration of parallel plates is called a capacitor and is widely used to create constant electric fields inside.

 To obtain this field it is essential that the charge on the plates are of the same magnitude, but in the opposite direction

This is so that the fields created by each plate can be added inside and subtracted from the outside of the plates

5 0
3 years ago
Other questions:
  • Noah modeled a layer of the sun by showing how particles of rice move up and down in boiling water. Which layer of the sun did N
    9·2 answers
  • A toaster oven uses67,500 joules of energy in 45 seconds to toast a piece of bread what is the power of the oven
    12·1 answer
  • Why is the gravitational potential energy of an object 1 meter
    12·1 answer
  • Gravitational force between two objects increases as mass increases and distance
    12·1 answer
  • All vehicles are required to stop within how many feet of a railroad crossing when a train is approaching
    6·1 answer
  • Unimpressed with your previous stunt, the director of the new James
    7·1 answer
  • At what angle should an object be thrown so that the maximum range is equal to three times the height reached by the projectile?
    7·1 answer
  • Cassy shoots a large marble (Marble A, mass: 0.06kg) at a smaller marble (Marble B, mass: 0.03kg) that is sitting still. Marble
    15·1 answer
  • Complete the simulation for three different trails. Complete chart below, using the data for your simulation from each trail.
    9·2 answers
  • What is meant by the term 'total internal reflection'? (GCSE Level)
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!