Question

A 68 g bar of gold is cut into 3 equal pieces. How does the density of each piece compare to the density of the original gold bar?

Answer 1

68/3=22.66 so its a third of the original density

Answer 2

Answer:

The density would be same.

Step-by-step explanation:

$\because \text{Density}=\frac{\text{Mass}}{\text{Volume}}$

Here, the mass of the original box = 68 g,

Suppose V be the volume of the original box,

Then, the density of the original box = $\frac{68}{V}$

After cutting this box into 3 equal pieces,

Mass of each piece = $\frac{68}{3}$

While, the volume of each piece = $\frac{V}{3}$

So, the density of each piece = $\frac{68/3}{V/3}$ = $\frac{68}{V}$

Hence, the density would be same.