Calculate the molarity of 139 grams of sucrose, C12H22O11, in 2.60 liters of solution.
1 answer:
Answer:
to calculate the molarity of the said sucrose,
firstly calculate the moles
which is = Molecular weight of C12H22O11 = 342g/mol
then
moles = 139/342
= 0.41 moles
to calculate Molarity now
Molarity= moles of the solute/volume of solution in liter
=0.41/2.60
=0.158M
Explanation:
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1.00 x 10^-5 M
Explanation:
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