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Shkiper50 [21]
3 years ago
11

How many grams of beryllium phosphate are produced when 38 grams of beryllium oxide react with iron (III) phosphate?

Chemistry
1 answer:
Irina-Kira [14]3 years ago
3 0

solve using the chemical equation and molar mass

Explanation:

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The largest ruby isnthe world is 10.9 cm long, 9.1 cm wide and 5.8 cm thick, giving
Maslowich
You have to use density=mass/volume formula:


3.97= \frac{x}{575}

Solve for x and you get 2282.75 grams
6 0
3 years ago
The molecule with the largest dipole moment (a) co2 (b) h2o (c) ch4 (d) c2h4 (e) ph3
storchak [24]

The molecule with the largest dipole moment will be CH_{4}.

A dipole moment would be a unit used to describe how far apart two electrical charges are from one another. Dipole moments represent a type of vector. The direction could be from negative charge to positive charge, while the magnitude has been equal to the charge times the distance between most of the charges.

The polar bonds, of  CO_{2} as well as H_{2} O have chemical configurations where the polarity cancels, leaving no net dipole. Regardless of the molecule's shape, CH_{4} lacks a net dipole due to its non-polar links.

The molecule with the largest dipole moment will be CH_{4}.

Hence the correct answer will be option (c).

To know more about dipole moment

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3 0
2 years ago
A force of 2,500 pounds drags a truck 30 feet in 1/2 minute.
scoray [572]
The right subject for this question is physics.

To calculate the work you use the formula:

Work = force * displacement

Work = 2500 pounds * 30 feet = 75,000 pounds - feet



To calculate the power you use the formula:

power = work / time

Power = 75,000 pound - feet / 30 seconds = 2300 pound-feet / second.
3 0
3 years ago
You have a balloon filled with hellum that has a volume of 4.91 cubic decimeters
juin [17]

Answer:

32

Explanation:

because the number of heliem is your aswer

5 0
3 years ago
Read 2 more answers
Complete combustion of 2.60 g of a hydrocarbon produced 8.46 g of co2 and 2.60 g of h2o. what is the empirical formula for the h
zubka84 [21]
1 mole of carbon dioxide contains a mass of 44 g, out of which 12 g are carbon. 
Hence, in this case the mass of carbon in 8.46 g of CO2:
 (12/44) × 8.46 = 2.3073 g
 1 mole of water contains 18 g, out of which 2 g is hydrogen;
Therefore, 2.6 g of water contains;
 (2/18) × 2.6 = 0.2889 g of hydrogen.
Therefore, with the amount of carbon and hydrogen from the hydrocarbon we can calculate the empirical formula.
We first calculate the number of moles of each,
Carbon = 2.3073/12  = 0.1923 moles
Hydrogen = 0.2889/1 = 0.2889 moles
Then, we calculate the ratio of Carbon to hydrogen by dividing with the smallest number value;
             Carbon : Hydrogen
  0.1923/0.1923 : 0.2889/0.1923
                       1 :  1.5
                      (1 : 1.5) 2
                     = 2 : 3
Hence, the empirical formula of the hydrocarbon is C2H3
5 0
4 years ago
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