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3 years ago

When electrolyzing copper (ll) chloride, what reaction takes place at the anode? What reaction takes place at the cathode?

Chemistry

1 answer:

klemol [59]3 years ago

5 0

Answer:

Copper ions are reduced into copper atoms.

Cu²⁺₍aq₎ + 2e⁻ → Cu₍s₎

Explanation:

During electrolysis, the positive H⁺ and Cu⁺ ions move to the negative cathode and negative OH⁻ and Cl⁻ ions move to the positive anode.

At cathode, copper ions are preferentially discharged due to the low electromotive force required to discharge them compared to the hydrogen ion. The copper ions gain the two electrons lost by the chloride ions when the are discharged. (2 Cl⁻₍aq₎ → Cl₂₍g₎ + 2e⁻)

Thus the half equation is as follows:

Cu²⁺₍aq₎ + 2e⁻ → Cu₍s₎

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3 points

vfiekz [6]

Answer:

density=6.74g/ml

:320g÷47.5ml

d=6.74g/ml

thank you

I hope this is helpful

8 0

3 years ago

How many atoms are in 1 mole of Carbon tetrachloride?

lesantik [10]

Answer:

There is one carbon atom in every carbon tetrachloride molecule, which means that there is an equal number of carbon atoms to carbon tetrachloride molecules. 5.089 x 1022 atoms of C.

Explanation:

Hope this helped, Have a Wonderful Day!!

3 0

3 years ago

Does anyone know the answer to these?

Rashid [163]

Answer:

The answer to your question is below

Explanation:

Data

mass of CaCO₃ = 155 g

mass of HCl = 250 g

mass of CaCl₂ = 142 g

reactants = CaCO₃ + HCl

products = CaCl₂ + CO₂ + H₂O

1.- Balanced chemical reaction

CaCO₃ + 2HCl ⇒ CaCl₂ + CO₂ + H₂O

2.- Limiting reactant

molar mass of CaCO₃ = 40 + 12 + 48 = 100 g

molar mass of HCl = 2[1 + 35.5 ] = 73 g

theoretical proportion CaCO₃ /HCl = 100 / 73 = 1.37

experimental proportion CaCO₃ /HCl = 155 / 250 = 0.62

As the experimental proportion was lower than the theoretical proportion the limiting reactant is CaCO₃

3.-

Calculate the molar mass of CaCl₂

CaCl₂ = 40 + 71 = 111 g

100 g of CaCO₃ ------------------ 111 g of CaCl₂

155 g of CaCO₃ ----------------- x

x = (155 x 111) / 100

x = 17205 / 100

x = 172.05 g of CaCl₂

4.- percent yield

Percent yield = 142 / 172.05 x 100 = 82.5 %

5.- Excess reactant

100 g of CaCO₃ -------------------- 73 g of HCl

155 g of caCO₃ ------------------- x

x = (155 x 73)/100

x = 133.15 g

Mass of HCl = 250 - 133.15

= 136.9 g

4 0

2 years ago

If the molecular weight of a semiconductor is 27.9 grams/mole and the diamond lattice constant is 0.503 nm, what is the density

adelina 88 [10]

Explanation:

The given data is as follows.

Mass = 27.9 g/mol

As we know that according to Avogadro's number there are $6.023 \times 10^{26}$ atom present in 1 mole. Therefore, weight of 1 atom will be as follows.

1 atoms weight = $\frac{38}{6.023 \times 10^{26}}$

In a diamond cubic cell, the number of atoms are 8. So, n = 8 for diamond cubic cell.

Therefore, total weight of atoms in a unit cell will be as follows.

= $\frac{8 \times 27.9 g/mol}{6.023 \times 10^{26}}$

= $37.06 \times 10^{-26}$

Now, we will calculate the volume of a lattice with lattice constant 'a' (cubic diamond) as follows.

= $a^{3}$

= $(0.503 \times 10^{-9})^{3}$

= $0.127 \times 10^{-27} m^{3}$

Formula to calculate density of diamond cell is as follows.

Density = $\frac{mass}{volume}$

= $\frac{37.06 \times 10^{-26}}{0.127 \times 10^{-27} m^{3}}$

= 2918.1 $g/m^{3}$

or, = 0.0029 g/cc (as 1 $m^{3} = 10^{6} cm^{3}$ )

Thus, we can conclude that density of given semiconductor in grams/cc is 0.0029 g/cc.

4 0

3 years ago

why is iodine is a solid at STP but chlorine is a gas at STP? explain in terms of intermolecular forces.

Lerok [7]

Iodine is a solid at STP (standard room temperature and pressure) as the intermolecular forces between the iodide compound is strongly held by bonds such as electrostatic forces of attraction if its a ionic compound. Therefore STP is so sufficient enough to breakthrough these bonds hence its a solid. However, chlorine’s a gas as its intermolecular bonds are weak, and STP is strong enough to break these bonds of where chlorine is a gas

NOTE: they should really give you a compound so you can identify between covalent and ionic bonds and talk about it in more depth

7 0

3 years ago