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Andrew [12]
3 years ago
8

When electrolyzing copper (ll) chloride, what reaction takes place at the anode? What reaction takes place at the cathode?

Chemistry
1 answer:
klemol [59]3 years ago
5 0

Answer:

Copper ions are reduced into copper atoms.

Cu²⁺₍aq₎ + 2e⁻ →  Cu₍s₎

Explanation:

During electrolysis,  the positive H⁺ and Cu⁺ ions move to the negative cathode and negative OH⁻ and Cl⁻ ions move to the positive anode.

At cathode, copper ions are preferentially discharged due to the low electromotive force required to discharge them compared to the hydrogen ion. The copper ions gain the two electrons lost by the chloride ions when the are discharged. (2 Cl⁻₍aq₎ → Cl₂₍g₎ + 2e⁻)

Thus the half equation is as follows:

Cu²⁺₍aq₎ + 2e⁻ →  Cu₍s₎

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17. Explain why chlorine gas can be prepared by electrolyzing an aqueous solution of NaCl
yulyashka [42]

Answer:

Fluorine gas reacts with water.

8 0
3 years ago
Which of the following weighs least?
Lunna [17]

Answer:

A

Explanation:

0.2g of atom of nitrogen is the one that weigh least cause of.2g is not up to one mole of nitrogen

7 0
3 years ago
What must occur in a substance in order to determine a chemical property?
MissTica
Change(A chemical reaction.)
6 0
3 years ago
Read 2 more answers
14. A piece of titanium at 100.0°C was dropped into 50.0 g of water at 20.0°C. The final temperature of the system was 22.6°C. W
Gemiola [76]

Answer:

m_{Ti}=13.0g

Explanation:

Hello,

In this case, based on the given, we can infer that as titanium is hot and water cold, it cools down whereas the water is heated up, therefore, in terms of heat, we have that the heat lost by the titanium is gained by the water:

-Q_{Ti}=Q_{H_2O}

That in terms of mass, specific heat and temperatures is:

-m_{Ti}Cp_{Ti}(T_2-T_{Ti})=m_{H_2O}Cp_{H_2O}(T_2-T_{H_2O})

In such a way, for computing the mass of titanium, considering the heat capacity of water 4.18 J/g°C, we have:

m_{Ti}=\frac{m_{H_2O}Cp_{H_2O}(T_2-T_{H_2O})}{-Cp_{Ti}(T_2-T_{Ti})} \\\\m_{Ti}=\frac{50.0g*4.18\frac{J}{g\°C}(22.6-20.0)\°C}{-0.54\frac{J}{g\°C}*(22.6-100.0)\°C} \\\\m_{Ti}=13.0g

Regards.

8 0
3 years ago
How do I set this up?
Allisa [31]

Answer: -

280mg

Explanation: -

The chemical formula is C14H18N2O5

Molar mass of the compound = 12 x 14 + 1 x 18 + 14 x 2 + 16 x 5 = 294 gram

Number of nitrogen atoms present in the formula = 2

Mass of nitrogen present= 14 x 2 = 28 gram

Thus 294 gram of the compound has 28 gram.

Hence 2.95grams of the compound has (28 gram x 2.95 gram / 294 gram)

= 0.28 gram

= 280 mg

Thus 280 mg of nitrogen is present in 2.95 grams of C14H18N2O5

4 0
3 years ago
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