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nataly862011 [7]
3 years ago
13

3.0 L of a gas has a temperature of 78 C find the volume of the gas at standard temperature

Chemistry
2 answers:
jeka57 [31]3 years ago
4 0

Answer:

= 2.33 L

Explanation:

V1/T1 = V2/T2

V1 = 3.0 L

T1 = 78 + 273

   = 351 K

At s.t.p the temperature is 273 K and pressure is 1 atm.

V2 = ?

T2 = 273 K

V2 = V1T2/T1

    = (3.0 ×273)/351

    = 2.33 L

Explanation:

ik it is confusing but that is what i got

skelet666 [1.2K]3 years ago
3 0

Answer:

Thanks

Explanation:

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