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maks197457 [2]
3 years ago
12

A 1.4 kg block slides across a rough surface such that it slows down with an acceleration of 1.25 m/s(squared). What is the coef

ficient of kinetic friction between the block and the surface?
Help please. Show steps. ...?
Physics
1 answer:
tino4ka555 [31]3 years ago
5 0
F = ma 

<span>where </span>

<span>F = frictional force </span>
<span>m = mass of the block = 1.4 kg (given) </span>
<span>a = acceleration of the block = 1.25 m/sec^2 (given) </span>

<span>Substituting values, </span>

<span>F = (1.4)(1.25) </span>

<span>F = 1.75 N </span>

<span>By definition, </span>

<span>F = (mu)(Normal force) </span>

<span>where </span>

<span>mu = coefficient of friction </span>
<span>Normal force = mg = 1.4*9.8 = 13.72 </span>

<span>Again, substituting appropriate values, </span>

<span>1.75 = mu(13.72) </span>

<span>mu = 0.128</span>
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