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Irina18 [472]
3 years ago
6

Please Help!

Physics
2 answers:
sukhopar [10]3 years ago
4 0
<span>C. Infrared waves have lower frequency than UV rays.</span>
vivado [14]3 years ago
4 0

Answer:

C

Explanation:

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A spring with a mass of 5 Kg has natural length 0.5m. A force of 35.6 N is required to maintain it stretched to a length of 0.5m
aleksandrvk [35]

Answer:

Explanation:

force constant of spring  k = force / extension

= 35.6 / 0.5

k = 71.2 N / m

angular frequency ω of oscillation by spring mass system

\omega = \sqrt{\frac{k}{m} }

where m is mass of the body attached with spring

Putting the values

\omega = \sqrt{\frac{71.2}{5} }

ω = 3.77 radian / s

The oscillation of the mass will be like SHM having amplitude of 0.5 m and angular frequency of 3.77 radian /s . Initial phase will be π / 2

so the equation for displacement from equilibrium position that is middle point can be given as follows

x = .5 sin ( ω t + π / 2 )

= 0.5 cos ω t

= 0.5 cos 3.77 t .

x = 0.5 cos 3.77 t .

8 0
3 years ago
The loudness of a sound is the wave's _______
Burka [1]
Amplitude:)

Hope this help!
5 0
3 years ago
Read 2 more answers
Light of a given wavelength is used to illuminate the surfacce of a metal, however, no photoelectrons are emitted. In order to c
Jlenok [28]

Answer:

B. use light of a shorter wavelength.

Explanation:

We know that

E= \frac{hc}{\lambda}

h= plank's constant

c= speed of light

λ= wavelength of the incident light

so, in order to have sufficient energy for for the emission of electron, the incident's radiation must have λ small enough.

B. use light of a shorter wavelength.

6 0
3 years ago
How long will your trip take if you travel 4000 m at an average speed of 8m/s
SpyIntel [72]
  • Answer:

<em>500 sec</em>

<em>8 min 20 sec</em>

  • Explanation:

<em>Hi there !</em>

<em />

<em>8 m ................ 1 s </em>

<em>4000 m ........ x s</em>

<em>x = 4000m×1s/8m = 500 sec = 8 min 20 sec</em>

<em />

<em>Good luck ! </em>

8 0
3 years ago
Read 2 more answers
(a) What is the escape speed on a spherical asteroid whose radius is 545 km and whose gravitational acceleration at the surface
Keith_Richards [23]

Answer:

1777.92 m/s

Explanation:

R = Radius of asteroid = 545 km

M = Mass of planet

g = Acceleration due to gravity = 2.9 m/s²

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

Acceleration due to gravity is given by

g=\dfrac{GM}{R^2}\\\Rightarrow M=\dfrac{gR^2}{G}

The expression of escape velocity is given by

v=\sqrt{\dfrac{2GM}{R}}\\\Rightarrow v=\sqrt{\dfrac{2G}{R}\dfrac{gR^2}{G}}\\\Rightarrow v=\sqrt{2gR}\\\Rightarrow v=\sqrt{2\times 2.9\times 545000}\\\Rightarrow v=1777.92\ m/s

The escape speed is 1777.92 m/s

3 0
3 years ago
Read 2 more answers
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