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joja [24]
3 years ago
6

I need help, ASAP, I know what thermal energy is, but how does a skater use it when on the track?

Physics
1 answer:
Flauer [41]3 years ago
4 0

Answer: Looked it up but

Explanation:

When the skater lands on the track, the vertical component of his kinetic energy is converted to thermal energy. You can do experiments where there is no loss to thermal energy (only PE and KE conversions) by turning friction off and by making sure the skater doesn't leave the track.

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(b) Two containers made of insulating material contain the same volume of water at room
masha68 [24]

Answer:

the volume of liquid decreased due to evaporation from the exposed free surface of water so molecules got evaporated .

evaporation occurs at room temperature.

5 0
2 years ago
jill's car has a maximum acceleration of 8.7 miles per hour per second. how many seconds does it take her to acceleration from 0
amm1812
T = ?
v1 = 0mph
v2 = 60mph
a = 8.7mph/s

a =  \frac{v2 - v1}{t}
 \\ t =  \frac{v2-v1}{a}
 \\ t =  \frac{60mph - 0mph}{8.7mph/s}
 \\ t = 6.90s

Therefore, it takes 6.90 seconds for Jill to accelerate from 0 to 60 miles per hour.
4 0
3 years ago
Please hellllooooppp
Lena [83]

Answer:

to the east i would say as i have tryed looking it up and carnt fimd the answer so i would saythe east or the north

Explanation:

you should choose as i dont no as it is a toss between those two

8 0
2 years ago
1 point glitch if it works
raketka [301]

Answer:

lets see :)

Explanation:

8 0
3 years ago
Read 2 more answers
When some stars use up their fuel, they undergo a catastrophic explosion called a supernova. This explosion blows much or all of
algol13

Answer:

0.0768 revolutions per day

Explanation:

R = Radius

\omega = Angular velocity

As the mass is conserved the angular momentum is conserved

I_1\omega_1=I_2\omega_2\\\Rightarrow \frac{I_1}{I_2}=\frac{\omega_2}{\omega_1}

Moment of intertia for solid sphere

I_1=\frac{2}{5}MR^2\\\Rightarrow I_1=0.4MR^2

Moment of intertia for hollow sphere

I_2=\frac{2}{3}M(4.3R)^2\\\Rightarrow I_2=12.327MR^2

Dividing the moment of inertia

\frac{I_1}{I_1}=\frac{0.4MR^2}{12.327MR^2}\\\Rightarrow \frac{I_1}{I_2}=0.032

From the first equation

\omega_2=\omega_1\frac{I_1}{I_2}\\\Rightarrow \omega_2=2.4\times 0.032\\\Rightarrow \omega_2=0.0768\ rev\day

The angular velocity, in revolutions per day, of the expanding supernova shell is 0.0768 revolutions per day

8 0
3 years ago
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