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valentinak56 [21]
3 years ago
8

Please help me find the equations guys

Physics
1 answer:
Alexeev081 [22]3 years ago
4 0

The line at the bottom of the picture ... probably the first line on a list of choices  .. is the correct equation.

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Photo below with question, please help need to confirm answer<br> Is the answer A?
GarryVolchara [31]

Answer:

Only circuit A will contain to lit bulbs

3 0
3 years ago
A conductor of radius r, length l and resistivity p has resistance R. It is melted down and formed into a new conductor, also cy
Vaselesa [24]

Answer:

b) R/4 (There seems to an error in mentioning the multiple choices of this question, please see below explanation of correct calculations for this  question.)

Explanation:

dimension of the conductor before melting is l, r

reistivity is p

R=(p*l)/(pie*r2)

after reforming length is reduced to L=l/4

volume in both the cases will be same

i.e. pie * r^2 * l =pie * R^2 * L

r^2 * l = R^2 * (1/2)l

due to this radius will become R=sqrt(2) * r

now new reistance is given by Rx=(p * L)/(pie * R^2)

i.e. Rx=(p * l/2)/(pie * r^2 * 2)

after simplification RX=((p * l)/(pie * r^2))/4

i.e. Rx=R/4

5 0
3 years ago
Read 2 more answers
The development of nuclear power has provided electricity for less money, but at a cost. What may be considered a "cost" of nucl
Jlenok [28]
Nuclear power generates alot of power, ALOT. It requires Uranium and other radioactive substances to power it, which over time can degrade and become depleted. This radioactive waste would have to be placed somewhere, and it accumulates over time slowly. 
8 0
4 years ago
You are on a new planet, and are trying to use a simple pendulum to find the gravity experienced on this new planet. You find th
levacccp [35]

To solve this problem it is necessary to apply the concepts related to the Period based on the length of its rope and gravity, mathematically it can be expressed as

T= 2\pi \sqrt{\frac{L}{g}}

g = Gravity

L = Length

T = Period

Re-arrange to find the gravity we have

g = \frac{4\pi^2 L}{T^2}

Our values are given as

L = 0.35m\\T = 2s\\

Replacing we have

g = \frac{4\pi^2 L}{T^2}

g = \frac{4\pi^2 0.35}{2^2}

g = 3.45 m/s^2

Therefore the correct answer is C.

4 0
3 years ago
An object is placed at a far distance in front of a thin converging lens. Then the object (1 point) moves gradually toward the l
xeze [42]

Answer:

real, and then virtual

Explanation:

A converging lens is known as convex lens. This lens is called converging lens because it converges all light rays incident on the lens and parallel to the principal axis at the focus.

The nature of image formed by objects placed in front of this lens as mostly REAL IMAGES. The image formed becomes virtual only when the object is almost in close contact with the lens.

Based on the explanation, it can be deduced that an object placed far from a convex lens forms real images but as we move closer to the lens (almost touching the lens), the image formed overtime tends to be virtual.

8 0
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