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dybincka [34]
4 years ago
7

Chemistry is the study of God's

Physics
1 answer:
Alenkasestr [34]4 years ago
4 0
Yes yes I do believe that for sure
You might be interested in
An object of mass 82kg is accelerated upward at 3.2m/s/s. what force is required
vampirchik [111]

F = m · a

In order to accelerate 82 kg upward at the rate of 3.2 m/s², a NET upward force of (82kg · 3.2m/s²) =  262.4 Newtons is required.

But if the object is on or near the surface of the Earth, then there's a downward force of (82kg · 9.8m/s²) = 803.6 N already acting on it because of gravity.

So you need to apply (803.6N + 262.4N) = <em>1,066 Newtons UPward</em>, in order to cancel its own weight and accelerate it upward at that rate.  

6 0
4 years ago
Un cuerpo suspendido en el aire es capaz de:
Rama09 [41]

Answer:

Explanation:

d

5 0
3 years ago
A car slows down at -5.00 m/s^2 until it comes to a stop after travelling 15.0 m. How much time did it take to stop?
Xelga [282]
In physics, there are already derived equation that are based on Newton's Law of Motions. The rectilinear motions at constant acceleration have the following equations:

x = v₁t + 1/2 at²
a = (v₂-v₁)/t

where
x is the distance travelled
v₁ is the initial velocity
v₂ is the final velocity
a is the acceleration
t is the time

Now, we solve first the second equation. Since it mentions that the car comes eventually to a stop, v₂ = 0. Then,

-5 = (0-v₁)/t
-5t = -v₁
v₁ = 5t

We use this new equation to substitute to the first one:
x = v₁t + 1/2 at²
15 = 5t(t) + 1/2(-5)t²
15 = 5t² - 5/2 t²
15 = 5/2 t²
5t² = 30
t² = 30/5 = 6
t = √6 = 2.45

Therefore, the time it took to travel 15 m at a deceleration of -5 m/s² is 2.45 seconds.

5 0
3 years ago
I’m not sure how to solve this
spayn [35]

Answer:

Option 10. 169.118 J/KgºC

Explanation:

From the question given above, the following data were obtained:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1.61 KJ

Mass of metal bar = 476 g

Specific heat capacity (C) of metal bar =?

Next, we shall convert 1.61 KJ to joule (J). This can be obtained as follow:

1 kJ = 1000 J

Therefore,

1.61 KJ = 1.61 KJ × 1000 J / 1 kJ

1.61 KJ = 1610 J

Next, we shall convert 476 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

476 g = 476 g × 1 Kg / 1000 g

476 g = 0.476 Kg

Finally, we shall determine the specific heat capacity of the metal bar. This can be obtained as follow:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1610 J

Mass of metal bar = 0.476 Kg

Specific heat capacity (C) of metal bar =?

Q = MCΔT

1610 = 0.476 × C × 20

1610 = 9.52 × C

Divide both side by 9.52

C = 1610 / 9.52

C = 169.118 J/KgºC

Thus, the specific heat capacity of the metal bar is 169.118 J/KgºC

6 0
3 years ago
The Earth's magnetic field is approximately 0.5 Gauss. What is the magnetic energy density of this field
ser-zykov [4K]

Answer:

The  magnetic energy density  is  E_B  =  9.95 *10^{-4} \  J/m^3

Explanation:

From the question we are told that  

    The  earths magnetic field is  B  =  0.5 \  Gauss

Now

          1 \ Gauss  \to  1 *10^{-4} \ T

=>        0.5  \ Gauss  \to  x T

So  

          x =  \frac{0.5 *  1*10^{-4}}{1}

          x = B= 5.0 *10^{-5} \  T

Generally the magnetic energy density is  mathematically represented as

        E_B  =  \frac{B^2}{ 2 *  \mu_o  }

  Here \mu_o is the  permeability of  free space with a constant value

          \mu_o  =  4\pi * 10^{-7} N/A^2

substituting values for equation above  

       E_B  =  \frac{(5*10^{-5})^2}{ 2 *   4\pi * 10^{-7}  }

       E_B  =  9.95 *10^{-4} \  J/m^3

5 0
3 years ago
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