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3 years ago

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[BWS.02] Jim plans to plant coffee beans on the farm. Coffee needs warm, moist, and sunny climate. It always snows for four mont

hs, starting from November, in the location where Jim lives. The temperature is generally moderate from June to October. Based on scientific knowledge, which of these would be the best month to plant coffee?

2 answers:

dusya [7]3 years ago

5 0

I believe the answer is July.

ExtremeBDS [4]3 years ago

4 0

Answer:

july

Explanation:

it will be the best climate for the plant to thrive

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You have a bowling ball with a mass of 4kg. You throw it with an acceleration of 10 m/s/s. With how much force will it hit the p

Eddi Din [679]

Answer:

<h3>The answer is 40 N</h3>

Explanation:

The force acting on an object can be found by using the formula

<h3>force = mass × acceleration</h3>

From the question

mass = 4 kg

acceleration = 10 m/s²

So we have

force = 4 × 10

We have the final answer as

<h3>40 N</h3>

Hope this helps you

6 0

4 years ago

An ideal parallel-plate capacitor consists of two parallel plates of area A separated by a distance d. This capacitor is connect

Elina [12.6K]

Answer:

e) half

Explanation:

as we know relation b/w charge(Q) , capacitance (C) and voltage (V) is

Q = CV ...........(i)

we also know capacitance of a capacitor for separation d and area A is

C = ∈₀A/d ...........(ii)

from the above equation it is clear that C is inversely proportional to separation if separation doubled capacitance will reduced to half and from equation first charge is directly proportional to capacitance.

that s why magnitude of charge will reduced to half

so option (e) is right answer

3 0

3 years ago

Neeeee rnnnn ASAP offering 55 points CER: Brielle pushes a shopping cart through the store with an acceleration of 2

BartSMP [9]

Answer:

Decease the mass

Increase the force applied

Explanation:

To increase the acceleration of the shopping cart, Brielle should reduce the load inside her cart.

According to Newton's second law of motion;

Force = mass x acceleration

Now, mass is indirectly proportional to the acceleration. The more the mass, the lower the acceleration a body will generate.

Lighter bodies moves with a faster acceleration.

In this case the force applied is constant.

If the force applied is also, increased the acceleration of the body will increase also.

8 0

3 years ago

31. If you threw a baseball straight out at 45 m/s from a height of 1.5 meters (A) how long would it be in the air? B) How far o

coldgirl [10]

Answer:

A) t = 0.55 s

B) x = 24.8 m

Explanation:

A) We can find the time at which the ball will be in the air using the following equation:

$y_{f} = y_{0} + v_{0y}t - \frac{1}{2}gt^{2}$

Where:

$y_{f}$ is the final height= 0

$y_{0}$ is the initial height= 1.5 m

$v_{0y}$ is the component of the initial speed in the vertical direction = 0 m/s

t: is the time =?

g: is the gravity = 9.81 m/s²

$0 = 1.5 m - \frac{1}{2}9.81 m/s^{2}t^{2}$

By solving the above equation for t we have:

$t = \sqrt{\frac{2*1.5 m}{9.81 m/s^{2}}} = 0.55 s$

Hence, the ball will stay 0.55 seconds in the air.

B) We can find the distance traveled by the ball as follows:

$x_{f} = x_{0} + v_{0x}t + \frac{1}{2}at^{2}$

Where:

a: is the acceleration in the horizontal direction = 0

$x_{f}$ is the final position =?

$x_{0}$ is the initial position = 0

$v_{0x}$ is the component of the initial speed in the horizontal direction = 45 m/s

$x_{f} = x_{0} + v_{0x}t + \frac{1}{2}at^{2}$

$x_{f} = 0 + 45 m/s*0.55 s + 0 = 24.8 m$

Therefore, the ball will travel 24.8 meters.

I hope it helps you!

3 0

3 years ago

A disk of radius 10 cm speeds up from rest. it turns 60 radians reaching an angular velocity of 15 rad/s. what was the angular a

timurjin [86]

Answer:

a) The angular acceleration is 1.875 radians per square second.

b) The time taken by the disk to reach the final angular speed is 8 seconds.

Explanation:

a) Let suppose that the disk accelerates uniformly, given that initial and final angular speed ( $\omega_{o}$ , $\omega_{f}$ ), in radians per second, and change in angular position ( $\Delta \theta$ ), in radians, are known. The angular acceleration ( $\alpha$ ), in radians per square second, are found by using this expression:

$\alpha = \frac{\omega_{f}^{2}-\omega_{o}^{2}}{2\cdot \Delta \theta}$ (1)

If we know that $\omega_{o} = 0\,\frac{rad}{s}$ , $\omega_{f} = 15\,\frac{rad}{s}$ and $\Delta \theta = 60\,rad$ , then the angular acceleration of the disk is:

$\alpha = \frac{\omega_{f}^{2}-\omega_{o}^{2}}{2\cdot \Delta \theta}$

$\alpha = 1.875\,\frac{rad}{s^{2}}$

The angular acceleration is 1.875 radians per square second.

b) The time taken by the disk to reach the final angular velocity is determined by the following kinematic formula:

$t = \frac{\omega_{f}-\omega_{o}}{\alpha}$ (2)

Where $t$ is the time, in seconds.

If we know that $\omega_{o} = 0\,\frac{rad}{s}$ , $\omega_{f} = 15\,\frac{rad}{s}$ and $\alpha = 1.875\,\frac{rad}{s^{2}}$ , then the time taken by the disk is:

$t = \frac{\omega_{f}-\omega_{o}}{\alpha}$

$t = 8\,s$

The time taken by the disk to reach the final angular speed is 8 seconds.

8 0

3 years ago