A device that detects small current differences and prevents electrocution that is often required as a safety measure for bathroom, kitchen, and exterior outlets is referred to as: Ground-fault interrupter.
<h3>What are
arc-fault circuit interrupter?</h3>
According to "Article 100 Arc-Fault Circuit interrupter (AFCI)," arc-fault circuit interrupter is an electrical device which is designed and developed to deenergize the electrical circuit whenever it detects and recognizes characteristics unique to arcing.
Similarly, a ground-fault interrupter simply refers to an electrical device that is designed and developed for the detection of small current differences in an electrical circuit.
The main purpose of a ground-fault interrupter is to prevent electrocution or electrical shock and as such, it is an important safety measure for the following areas in a building:
- Bathroom
- Kitchen
- Exterior outlets
Read more on ground-fault interrupter here: brainly.com/question/12615861
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You haven't included the list of choices that goes with the question, so it's
impossible for me to choose the correct one, or to help you choose it.
Regarding my ability to answer the question and collect the 5-point bounty,
I'm free to make up any phrase of my own that correctly describes an atom.
-- very very very very very very very tiny
-- includes even tinier particles, with electric charges
both positive and negative
-- smaller than the wavelength of visible light
Answer:
1.843 x 10^-5 C
Explanation:
<u><em>Givens:
</em></u>
It is given that the air starts ionizing when the electric field in the air exceeds a magnitude of 3 x 10^6 N/C, which means that the max electric field can stand without forming a spark is 3 x 10^6 N/C.
Also it is given that the radius of the disk is 50 cm, it is required to find out the max amount of charge that the disk can hold without forming spark, which means the charge that would produce the max magnitude of the electric field that air can stand without forming spark, and since we know that the electric field in between 2 disk "Capacitor" is given by the following equation
E = (Q/A)/∈o (1)
Where,
Q: total charge on the disk.
A: the area of the disk.
<u><em>Calculations: </em></u>
We want to find the quantity of charge on the disk that would produce an electric field of 3 x 10^6 N/C, knowing the radius of the disk we can find the cross-section of the disk, thus substituting in equation (1) we find the maximum quantity of charge the disk can hold
Q = EA∈o
= (3 x 10^6) x (π*0.50) x (8.85 x 10^-12)
= 1.843 x 10^-5 C
note:
calculations maybe wrong but method is correct
Answer:
3 volts
Explanation:
It is given that,
Magnetic field, B = 0.8 T
Length of a conducting rod, l = 50 cm = 0.5 m
Velocity of the conducting rod, v = 7.5 m/s
We need to find the magnitude of the emf induced in the rod when it is moving toward the right. When a rod is moved in a magnetic field, an emf is induced in it and it is given by :
Putting all the values,
So, the magnitude of the emf induced in the rod is 3 volts.
Answer:
186 N
ExplanatioN
Weight is essentially just a measurement of the force of gravity, so you can use this equation.
F = mg
Force = Mass × Acceleration due to Gravity
F = 19kg × 9.8m/s^2. (Acceleration due to Gravity on Earth.)
F = 186.02N
