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3 years ago

6

The net force determines how and if an object will BLANK thank youuuu

1 answer:

SCORPION-xisa [38]3 years ago

5 0

Move with constant speed or accelerate and will determine direction

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PLEASE HELP!!!!!!!! NEED DONE SOON!!!

zhannawk [14.2K]

Answer:

the object is decelerating

4 0

3 years ago

Read 2 more answers

A car is parked on a cliff overlooking the ocean on an incline that makes an angle of 24.0° below the horizontal. The negligent

anzhelika [568]

Answer:

The position is $P = 47.4 \ m$ relative to the base of the ocean

Explanation:

From the question we are told that

The angle made by the incline with the horizontal is $\theta = 24.0 ^o$

The constant acceleration is $a = 3.82 \ m/s^2$

The distance covered is $d = 60.0 \ m$

The height of the cliff is $h = 50 .0 \ m$

The velocity of the car is mathematically represented as

$v^2 = u^2 + 2ad$

The initial velocity of the car is u= 0

So

$v^2 = 2ad$

substituting values

$v^2 = 2 * 3.82 * 60$

$v = 21.4 \ m/s$

The vertical component of this velocity is

$v_v = -v * sin(\theta )$

substituting values

$v_v = -21.4 * sin(24.0)$

$v_v = -8.7 \ m/s$

The negative sign is because is moving in the negative direction of the y-axis

The horizontal component of this velocity is

$v_h = v * cos (\theta)$

$v_h = 21.4 * cos (24.0)$

$v_h = 19.5 \ m/s$

Now according to equation of motion we have

$h = v_v*t - \frac{1}{2} * g t^2$

substituting values

$50 = -8.7 t - \frac{1}{2} * 9.8 t^2$

$4.9t^2 +8.7t -50 = 0$

using quadratic equation we have that

$t_1 = 2.42\ s \ and\ t_2 = -4.20\ s$

given that time cannot be negative

$t = 2.42 \ s$

The car’s position relative to the base of the cliff when the car lands in the ocean is mathematically evaluate as

$P = v_h * t$

substituting values

$P = 19.5 * 2.43$

$P = 47.4 \ m$

5 0

3 years ago

Which of the following is an example of rotation

SOVA2 [1]

I believe it is D. Earth spinning on it's axis.

8 0

3 years ago

An electron moving with a velocity v= 5.0 × 107 m/s i enters a region of space where perpendicular electric and a magnetic field

liq [111]

Answer:

The magnetic field that will allow the electron to go through the region without being deflected is $2\times 10^{-4}\ T$ .

Explanation:

Given that,

Velocity of the electron, $v=5\times 10^7\ m/s$

Electric field, $E=10^4\ V/m\ j$

We need to find the magnetic field that will allow the electron to go through the region without being deflected. It can be calculated as :

$qE=qvB\ \sin\theta$

Here, $\sin\theta=90^{\circ}$

$E=vB\\\\B=\dfrac{E}{v}\\\\B=\dfrac{10^4}{5\times 10^7}\\\\B=2\times 10^{-4}\ T$

So, the magnetic field that will allow the electron to go through the region without being deflected is $2\times 10^{-4}\ T$ .

6 0

3 years ago

20 Points available for physics help

Sonja [21]

The second one is correct not sure about the first one sorry

8 0

3 years ago

Read 2 more answers