It’s important for a scientist to be open-minded because they need to be able to understand or creative anything that was never thought about. It’s also important for a scientist to be skeptical because some ideas or products that they hear about can have false factors. I hope this helped!
Answer:
M=28.88 gm/mol
Explanation:
Given that
T= 95 K
P= 1.6 atm
V= 4.87 L
m = 28.6 g
R=0.08206L atm .mol .K
We know that gas equation for ideal gas
P V = n R T
P=Pressure , V=Volume ,n=Moles,T= Temperature ,R=gas constant
Now by putting the values
P V = n R T
1.6 x 4.87 = n x 0.08206 x 95
n=0.99 moles
We know that number of moles given as
M=Molar mass
M=28.88 gm/mol
Answer:
find the diagram in the attachment.
Explanation:
Let vi = 12 m/s be the intial velocy when the ball is thrown, Δy be the displacement of the ball to a point where it starts returning down, g = 9.8 m/s^2 be the balls acceleration due to gravity.
considering the motion when the ball thrown straight up, we know that the ball will come to a stop and return downwards, so:
(vf)^2 = (vi)^2 + 2×g×Δy
vf = 0 m/s, at the highest point in the upward motion, then:
0 = (vi)^2 + 2×g×Δy
-(vi)^2 = 2×g×Δy
Δy = [-(vi)^2]/2×g
Δy = [-(-12)^2]/(2×9.8)
Δy = - 7.35 m
then from the highest point in the straight up motion, the ball will go back down and attain the speed of 12 m/s at the same level as it was first thrown
Work is the force done to an object to bring about a displacement of the object.
when the block is being moved there are 2 forces acting on the block.
the force applied acts on the block in one direction bringing about its displacement in that direction. Theres another force called frictional force which acts against the movement of the block in the opposite direction to the direction in which the block is moving.
The resultant force acting on the block is ;
F = force applied - frictional force
frictional force - coefficient of friction *mg
mg - mass * gravitational acceleration
mg = 1 kg * 9.8 ms⁻²
= 9.8 N
frictional force = 0.5 * 9.8 N
= 4.9 N
resultant force = 20 N - 4.9 N
= 15.1 N
work done = force * distance moved
= 15.1 N * 3 m
= 45.3 J
To solve this problem we will apply the concepts related to the centripetal force, for which it is necessary to equate it with the static friction force of the body. From this, we will clear the speed and replace with the given values. Our values are defined as,
Maximum velocity can be find out using centripetal force,
Must be equal to,
Therefore the maximum speed that he can travel through the arc without slipping is 9.93m/s