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Lana71 [14]
3 years ago
6

The standard enthapy of combustion of solid urea co(nh2)2 is -632kjmol-1 at 298k​

Chemistry
1 answer:
Setler79 [48]3 years ago
8 0

Answer:

The standard enthalpy of combustion of solid urea ((CO(NH2)2) is -632 kJ mol-1 at 298 K and its standard molar entropy is 104.60 J K-1 mol-1

Explanation:

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Which represents the self ionization of water at 25 degrees
gayaneshka [121]
This question comes with four answer choices:

<span>A. H2O + H2O ⇄ 2H2 + O2

B. H2O + H2O⇄  H2O2 + H2

C. H2O + H2O ⇄ 4H+ + 2O2-

D. H2O + H2O ⇄  H3O+ + OH-

Answer: option </span><span>D. H2O + H2O ⇄  H3O+ + OH-

(the +sign next to H3O is a superscript, as well as the - sing next to OH)

Explanation:

The self-ionization of water, or autodissociation, produces the two ions H3O(+) and OH(-). The presence of ions is what explain the electrical conductivity of pure water.

</span><span>In this, one molecule of H2O loses a proton (H+) (deprotonates) to become a hydroxide ion, OH−. Then, he <span>hydrogen ion, H+</span>, immediately protonates another water molecule to form hydronium, H3O+.
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3 years ago
This balanced chemical equation represents a chemical reaction: 6no + 4nh3 → 5n2 + 6h2o what volume of nh3 gas, at standard temp
Liula [17]

The answer is: volume of ammonia gas is 7.4 L.

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M(NO) = 30 g/mol; molar mass of nitrogen(II) oxide.

V(NH₃) = ?

n(NO) = 15 g ÷ 30 g/mol.

n(NO) = 0.5 mol; amount of nitrogen(II) oxide.

From chemical reaction: n(NO) : n(NH₃) = 6 : 4.

0.5 mol : n(NH₃) = 6 : 4.

n(NH₃) = 0.33 mol; amount of ammonia.

Vm = 22.4 L/mol; molar volume at STP.

V(NH₃) = 0.33 mol · 22.4 L/mol..

V(NH₃) = 7.4 L.

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Answer:

Explanation:

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