Question

If water with a mass of 0.755 absorbs 0.954J of heat, how much will its temperature increase?

Answer 1

Answer:

B. 0.302.

Explanation:

• To solve this problem, we can use the relation:

Q = m.c.ΔT,

where, Q is the amount of heat absorbed by water (Q = 0.954 J).

m is the mass of water (m = 0.755 g).

c is the specific heat capacity of water (c = 4.186 J/g.°C).

ΔT is the temperature difference (final T - initial T) (ΔT =  ??? °C).

∴ ΔT = Q/m.c = (0.954 J)/(0.755 g)(4.186 J/g.°C) = 3.018 °C ≅ 3.02 °C.

Answer 2

Answer: Option (B) is the correct answer.

Explanation:

The given data is as follows.

      mass = 0.755 g,       Q = 0.954 J

  $\Delta T$ = ? ,       Specific heat of water, C = $4.18 J/g^{o}C$

As the relation between heat energy, mass and change in temperature are as follows.

              Q = $mC \Delta T$

           0.954 J = $0.755 g \times 4.18 J/g^{o}C \times \Delta T$

            $\Delta T = 0.302^{o}C$

Thus, we can conclude that increase in temperature is $0.302^{o}C$.