¿Que atomo gana el electron?

HNO3 is an Arrhenius acid and increases the concentration of what??? when added to water.

sineoko [7]

When nitric acid is added to water, the concentration of hydronium ions would increase since the nitric acid dissociates into ions, the hydronium ions and the nitrate ions. Hope this answers the question. Have a nice day. Feel free to ask more questions.

3 0

4 years ago

A soluble iodide was dissolved in water. Then an excess of silver nitrate, AgNO3, was added to precipitate all of the io- dide i

Sergeeva-Olga [200]

Answer:

$m_{I^-}=1.18gI^-$

Explanation:

Hello,

In this case, the reaction is given as:

$I^-+AgNO_3\rightarrow AgI+NO_3^-$

Thus, starting by the yielded grams of silver iodide, we obtain:

$n_{I^-}=2.185gAgI*\frac{1molAgI}{234.77gAgI}*\frac{1molI}{1molAgI}=9.31x10^{-3}molI^-$

Which correspond to the iodide grams in the silver iodide. In such a way, by means of the law of the conservation of mass, it is known that the grams of each atom MUST remain constant before and after the chemical reaction whereas the moles do not, therefore, the mass of iodine from the silver iodide will equal the mass of iodine present in the soluble iodide, thereby:

$m_{I^-}=9.31x10^{-3}molI^-\frac{127gI^-}{1molI^-} =1.18gI^-$

And the rest, correspond to the iodide's metallic cation which is unknown. Such value has sense since it is lower than the initial mass of the soluble iodide which is 1.454g, so 0.272 grams correspond to the unknown cation.

Best regards.

7 0

4 years ago

[25 pts] When a 14.2g sample of a compound containing only mercury and oxygen is decomposed, 13.2g of Hg is obtained. What is th

Agata [3.3K]

Answer:

% composition of Hg = 93 %

% composition of O = 7 %

Explanation:

Data Given:

mass of total sample = 14.2 g

mass of mercury (Hg) = 13.2 g

percent composition of Hg =

percent composition of O =

Solution:

First find mass of oxygen

As this compound only have two components that is oxygen and mercury

So

upon decomposition it gives 13.2 g mercury

now to find mass of oxygen we have to subtract mass of mercury from total mass of sample

Mass of oxygen = Total mass of sample - mass of Mercury

Mass of oxygen = 14.2 g - 13.2 g

Mass of oxygen = 1 g

Now to find percent composition of Hg and Oxygen

% composition = component mass / total mass of sample x 100. . . .(1)

For % composition of mercury Hg

Put values in equation 1

% composition of Hg = 13.2 g / 14.2 g x 100

% composition of Hg = 93%

For % composition Oxygen (O)

Put values in equation 1

% composition of O = 1 g / 14.2 g x 100

% composition of O = 7 %

6 0

3 years ago

X³-216?<br> can someone help me with this prob?

andre [41]

Cube root the -216 which will make x = cubedroot(-216) or x = -6

4 0

4 years ago

According to le chatelier's principle, increasing the pressure of the system shown below will shift equilibrium to the left (tow

jasenka [17]

N2(g) + 3H2(g) =2NH3(g)

Number of moles of reactants > product...
Therfore if pressure is increased.
Equilibrium is disturbed according to LCP....
Equilibrium shift to the right (product)
......
If you want to understant the fundamental concept:

Take for example 2A + 3B = 4C
Reactant: 5 moles (5 volumes)
Product: 4 moles (4 volumes)

When pressure of a gas is increased, volume decreases!
(Vice-versa)

If pressure is increased, volume decreases. Hence number of collisions INCREASES(constrain). Equilibrium shifts in such a direction so as to decrease the number of collision accordinf to LCP...
This happens when number of paeticles decreases as equilibrium shift forward because the forward reaction is accompanied by a decrease in number of particles (5 to 4)

4 0

4 years ago