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Eva8 [605]
3 years ago
12

¿Que atomo gana el electron?

Chemistry
1 answer:
antoniya [11.8K]3 years ago
3 0

Answer:

anion

Explanation:

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What is the atmospheric pressure?
White raven [17]

Answer:

The air pressure at sea level is about 14.7 pounds per square inch (psi). For every foot above sea level, the air pressure drops about 0.0005263 psi. According to this information, at about what height above sea level is the air pressure 13.2 psi?

7 0
2 years ago
Read 2 more answers
a solution contains 4.5 times 10 to the negative 3 M HCI. Determine the hydroxide concentreation of the solution.
frosja888 [35]
HCl ----------> H(+) + Cl(-)
0,0045-x.........x...........x
0..................0,0045...0,0045

pH = -log[H+]
pH = -log[0,0045]
pH = 2,347

pOH = 14-pH
pOH = 14-2,347
pOH = 11,653

pOH = -log[OH-]
[OH-] = 10^-pOH
[OH-] = 10^-11,653
[OH-] = 2,2233·10^-12 mol/dm³
3 0
2 years ago
A chemist adds a sample of an ideal gas to a balloon and measures its volume. The chemist removes some of the gas from the ballo
meriva

Answer:

The volume of the gas decreases also in a 21% based on the Avogadro's law

Explanation:

Based on Avogadro's law, the volume of a gas is directely proportional to the amount of moles of gas when temperature and pressure remain constants.

The formula is:

V1 / n1 = V2 / n2

<em>Where V is volume and n are moles in 1, initial state and 2, final state of the gas.</em>

<em />

At beginning, V1 = 100%, n1 = 100%,

As the chemist removes 21% of the gas, 79% of moles remain = n2.

Replacing:

100% / 100% = V2 / 79%

V2 = 79%, that means:

<h3>The volume of the gas decreases also in a 21% based on the Avogadro's law</h3>
8 0
2 years ago
A food substance kept at 0°C becomes rotten (as determined by a good quantitative test) in 8.3 days. The same food rots in 10.6
ZanzabumX [31]

Answer:

1.   67.2 kJ/mol

Explanation:

Using the derived expression from Arrhenius Equation

In \ (\frac{k_2}{k_1}) = \frac{E_a}{R}(\frac{T_2-T_1}{T_2*T_1})

Given that:

time t_1 = 8.3 days = (8.3 × 24 ) hours = 199.2 hours

time t_2 = 10.6 hours

Temperature T_1 = 0° C = (0+273 )K = 273 K

Temperature T_2 = 30° C = (30+ 273) = 303 K

Rate = 8.314 J / mol

Since (\frac{k_2}{k_1}=\frac{t_2}{t_1})

Then we can rewrite the above expression as:

In \ (\frac{t_2}{t_1}) = \frac{E_a}{R}(\frac{T_2-T_1}{T_2*T_1})

In \ (\frac{199.2}{10.6}) = \frac{E_a}{8.314}(\frac{303-273}{273*303})

2.934 = \frac{E_a}{8.314}(\frac{30}{82719})

2.934 = \frac{30E_a}{687725.766}

30E_a = 2.934 *687725.766

E_a = \frac{2.934 *687725.766}{30}

E_a =67255.58 \ J/mol

E_a =67.2 \ kJ/mol

7 0
2 years ago
What ions are formed when naoh is dissolved in water?.
valentina_108 [34]

Answer:

When sodium hydroxide (NaOH) dissolves in water, it separates into positively - charged sodium ions (cations) and negatively - charged hydroxide ions (anions).

Hope this helped.

7 0
2 years ago
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