Answer:
Explanation:
<u>Properties of a virtual image:</u>
1. Image formed cannot be projected or focused on a screen.
2. The distance of the object to the mirror is the same as the distance from the image to the mirror.
3. The size of the image formed is the same as the size of the object.
4. The image formed is laterally inverted. That is the right becomes left and vice versa.
5. The image is upright.
<u>Properties of a real image:</u>
1. Image formed can be projected on a screen.
2, The distance from the image to the mirror is not the same as the distance from the object to the mirror.
3. The size of the image is not the same as the size of the object.
4. Image formed is upside down.
Thomson proposed the "plum pudding" model - randomly scattered positive charges and negative charges held in a sphere
Rutherford disagreed with Thomson with his gold foil experiment - proposed that at the centre of an atom was a dense, positive mass and around it were very small negative charges called electrons
Answer:
28.7 m at 46.9°
Explanation:
The x component of the displacement is:
x = 6 m cos 0° + 25 m cos 57°
x = 19.6 m
The y component of the displacement is:
y = 6 m sin 0° + 25 m sin 57°
y = 21.0 m
The total displacement is found with Pythagorean theorem:
d = √(x² + y²)
d = 28.7 m
And the direction is found with trig:
θ = tan⁻¹(y/x)
θ = 46.9°
Answer:
E = 2k ![\frac{\lambda}{ r}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Clambda%7D%7B%20r%7D)
Explanation:
Gauss's law states that the electric flux equals the wax charge between the dielectric permeability.
We must define a Gaussian surface that takes advantage of the symmetry of the problem, let's use a cylinder with the faces perpendicular to the line of charge. Therefore the angle between the cylinder side area has the same direction of the electric field which is radial.
Ф = ∫ E . dA = E ∫ dA = q_{int} /ε₀
tells us that the linear charge density is
λ = q_ {int} /l
q_ {int} = l λ
we substitute
E A = l λ /ε₀
is area of cylinder is
A = 2π r l
we substitute
E =
E =
the amount
k = 1 / 4πε₀
E = 2k ![\frac{\lambda}{ r}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Clambda%7D%7B%20r%7D)
Answer:
6 amps
Explanation:by Kirchhoff's loop rule the current at any point in the loop must be equal or charge would be building up. The current at the ammeter is equally to the total current through the sun of the paths in parallel which it is in series with