Answer:
Explanation:
Ne has its outside shell full of electrons; therefore, its reaction with other elements is minimal if at all. Na, the next element, has 1 more proton and 1 more electron. More importantly that added electron is in the outside shell. It can fill that shell by ADDing 7 more electrons or LOSing the one electron. Obviously, it loses the one electron and it does so with gusto which makes Na a very reaction element while Ne is not reactive at all. Now follow oobleck's instructions, add what you read to what I've written,then summarize all of it in your own words.
The answer is an electric current.
Answer:
de Broglie wavelength of the bullet is 3.093 x 10⁻³⁵ m
Explanation:
Given;
mass of bullet, m = 28 g = 0.028 kg
velocity of the bullet, v = 765 m/s
de Broglie wavelength of the bullet is given by;
λ = h / mv
where;
λ is de Broglie wavelength of the bullet
h is Planck's constant = 6.626 x 10⁻³⁴ J/s
λ = h / mv
λ = (6.626 x 10⁻³⁴ ) / (0.028 x 765)
λ = 3.093 x 10⁻³⁵ m
Therefore, de Broglie wavelength of the bullet is 3.093 x 10⁻³⁵ m
"a black hole forms when any object reaches a certain critical density, and its gravity causes it to collapse to an almost infinitely small pinpoint."
I know its not straight forward with the answer
