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3 years ago

Describe how mass and distance affect gravitational force?

2 answers:

7 0

It depends. The strength of gravitational force between non other than two objects depends on two factors. Mass and distance. The force of gravity and masses exert on each other. Making a consequence if one of the masses are doubled, the force of gravity of the the objects is doubled.

Hope this helps.

Lerok [7]3 years ago

3 0

Explanation:

The Newton's law of gravitation gives the force acting between two bodies when they are separated by some distance. Mathematically, it is given by :

$F=G\dfrac{m_1m_2}{d^2}$

It shows that the gravitational force is directly proportional to the product of masses of two bodies and inversely proportional to the square of distance between them.

So, as the mass of bodies increases, the gravitational force increases and with the increase of distance between them, the gravitational force decreases.

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the ocean floor is, on average, 4267 m below sea level. What is the pressure in the atmosphere at this depth?

hichkok12 [17]

The pressure at the depth h in the ocean is given by (Stevin's law)
$p= p_0 + \rho g h$
where
$p_0 = 1.0 \cdot 10^5 Pa$ is the atmospheric pressure
and $\rho g h$ is the pressure exerted by the column of water of height h=4267 m, with $\rho = 1000 kg/m^3$ being the water density and $g=9.81 m/s^2$ .
Substituting, we find
$p=1.0 \cdot 10^5 Pa + (1000 kg/m^3)(9.81 m/s^2)(4267 m)=4.20 \cdot 10^7 Pa$
We want to convert this into atmospheres: we know that 1 atm corresponds to the atmospheric pressure at sea level, so $1 atm=1.0\cdot 10^5 Pa$ , therefore we just need to divide by this number:
$p= \frac{4.20 \cdot 10^7 Pa}{1.0 \cdot 10^5 Pa/atm} =420 atm$

7 0

3 years ago

A stone is thrown vertically upwards with a speed of 30.0 m/s.

matrenka [14]

Y₀ = initial position of the stone at the time of launch = 0 m

Y = final position of stone = 20.0 meters

a = acceleration = - 9.8 m/s²

v₀ = initial speed of stone at the time of launch = 30.0 m/s

v = final speed = ?

Using the equation

v² = v₀² + 2 a (Y - Y₀)

inserting the values

v² = 30² + 2 (- 9.8) (20 - 0)

v = 22.5 m/s

Y₀ = initial position of the stone at the time of launch = 0 m

Y = maximum height gained

a = acceleration = - 9.8 m/s²

v₀ = initial speed of stone at the time of launch = 30.0 m/s

v = final speed = 0 m/s

Using the equation

v² = v₀² + 2 a (Y - Y₀)

inserting the values

0² = 30² + 2 (- 9.8) (Y - 0)

Y = 46 m

6 0

3 years ago

A string with a length of 4.00 m is held under a constant tension. The string has a linear mass density of \mu=0.000600~\text{kg

yulyashka [42]

Answer:

$T=245.76N$

Explanation:

We know that the frequency of the nth harmonic is given by $f_n=nf$ , where $f$ is the fundamental harmonic. Since we have the values of two consecutive frequencies, we can do:

$f_{n+1}-f_n=(n+1)f-nf=nf+f-nf=f$

Which for our values means (we do not need the value of <em>n</em>, that is, which harmonics are the frequencies given):

$f=f_{n+1}-f_n=480Hz-400Hz=80Hz$

Now we turn to the formula for the vibration frequency of a string (for the fundamental harmonic):

$f=\frac{1}{2L} \sqrt{\frac{T}{\mu}}$

So the tension is:

$T=\mu(2Lf)^2$

Which for our values is:

$T=(0.0006kg/m)(2(4m)(80Hz))^2=245.76N$

6 0

3 years ago

If you were creating a lamp by hand what type of material would you chose for the wiring and what material would you chose to co

anzhelika [568]

Copper because it contains alot of electricity

6 0

4 years ago

Express 0.00000000062 kg in scientific notation. 6.2 x 1010kg 6.2 x 10-10kg 0.62 x 10-9kg

PilotLPTM [1.2K]

I believe the correct answer from the choices listed above is the second option. The scientific notation of the measurement 0.00000000062 kg would be <span>6.2 x 10^-10 kg. Scientific notation is used to express too large and too small values of numbers. Hope this helps. Have a nice day.</span>

7 0

3 years ago

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