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weqwewe [10]
3 years ago
9

Describe how mass and distance affect gravitational force?

Physics
2 answers:
ryzh [129]3 years ago
7 0
It depends. The strength of gravitational force between non other than two objects depends on two factors. Mass and distance. The force of gravity and masses exert on each other. Making a consequence if one of the masses are doubled, the force of gravity of the the objects is doubled.

Hope this helps.
Lerok [7]3 years ago
3 0

Explanation:

The Newton's law of gravitation gives the force acting between two bodies when they are separated by some distance. Mathematically, it is given by :

F=G\dfrac{m_1m_2}{d^2}

It shows that the gravitational force is directly proportional to the product of masses of two bodies and inversely proportional to the square of distance between them.

So, as the mass of bodies increases, the gravitational force increases and with the increase of distance between them, the gravitational force decreases.

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If the sprinter from the previous problem accelerates at that rate for 20 m, and then maintains that velocity for the remainder
kakasveta [241]

Question:

A 63.0 kg sprinter starts a race with an acceleration of 4.20m/s square. What is the net external force on him? If the sprinter from the previous problem accelerates at that rate for 20m, and then maintains that velocity for the remainder for the 100-m dash, what will be his time for the race?

Answer:

Time for the race will be t = 9.26 s

Explanation:

Given data:

As the sprinter starts the race so initial velocity = v₁ = 0

Distance = s₁ = 20 m

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Distance = s₂ = 100 m

We first need to find the final velocity (v₂) of sprinter at the end of the first 20 meters.

Using 3rd equation of motion

(v₂)² - (v₁)² = 2as₁ = 2(4.2)(20)

v₂ = 12.96 ms⁻¹

Time for 20 m distance = t₁ = (v₂ - v ₁)/a

t₁ = 12.96/4.2 = 3.09 s

He ran the rest of the race at this velocity (12.96 m/s). Since has had already covered 20 meters, he has to cover 80 meters more to complete the 100 meter dash. So the time required to cover the 80 meters will be

Time for 100 m distance = t₂ = s₂/v₂

t₂ = 80/12.96 = 6.17 s

Total time = T = t₁ + t₂ = 3.09 + 6.17 = 9.26 s

T = 9.26 s

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