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Vesna [10]
3 years ago
12

Solid water has the same molecules as liquid water. Is this true or false?

Physics
2 answers:
Vika [28.1K]3 years ago
6 0
Water can change from a liquid to a solid or a gas and back to a liquid, but its molecular structure always stays the same.
spayn [35]3 years ago
5 0

Answer:

True

Explanation:

Water molecules contain two hydrogen atoms bonded to one oxygen atom. The large oxygen atom has a stronger attraction for electrons than the small hydrogen atoms.

Water can change from a liquid to a solid or a gas and back to a liquid, but its molecular structure always stays the same.

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In order to induce electrical energy into a conductor or generator, what three factors must be present?
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The electricity produced by a generator works through the concepts of the following three factors; magnetic field, voltage and current. When a conductor with current flowing in it is placed in a magnetic field, it will cause the electrons to move in a direction perpendicular to the magnetic field. When working with generators, the guide for this direction is Fleming's Right Hand Rule. Since the electron move in perpendicular motion with magnetic field all the time, it would cause it to spin in a helical direction. These turns would then induce voltage and create electricity.
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PLZ answer asp The image shows the combustion of methane. Which equation represents this chemical reaction?
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The chemical reaction that would represent the combustion of methane would be CH4 + 2O2 = CO2 + 2H2O. Combustion reactions are reactions which involves a substance burning in oxygen.

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3 years ago
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The velocity of a particle (m = 10 mg, q = –4.0 μC) at t = 0 is 20 m/s in the positive x direction. If the particle moves in a u
kompoz [17]

Answer:

Vf = - 20 m/s ( -ve sign shows that the particle is moving opposite to positive x- direction).

Explanation:

Given:

Vi = 20 m/s, m= 10 mg =1 × 10⁻⁵ kg, q= -4.0 × 10⁻⁶ C , E= 20 N/C. t= 5.0 s

first to find Electric Force

F= Eq = 20 × -4.0 10⁻⁶ C = - 8 × 10⁻⁵ N (-ve sign shows that the field will push the particle opposite to positive x- direction)

We also have F=ma

⇒ a = F/m =  - 8 × 10⁻⁵ N / 10 × 10⁻⁵ kg = -8 m/s² ( -ve sign shows that the particle is accelerated opposite to positive x- direction)

Now according the first equation of Motion.

Vf = Vi + at

Vf = 20 m/s + -8 m/s² × 5 s

Vf= -20 m/s ( -ve sign shows that the particle is moving opposite to positive x- direction)

6 0
3 years ago
Consider the cylindrical weir of diameter 3 m and length 6m. If the fluid on the left has a specific gravity of 0.8, find the ma
sladkih [1.3K]

This question is incomplete, the complete question is;

Consider the cylindrical weir of diameter 3m and length 6m. If the fluid on the left has a specific gravity of 1.6 and on the right has a specific gravity of 0.8, Find the magnitude and direction of the resultant force.

Answer:

- the magnitude of the resultant force is 557.32 kN

- the direction of resultant force is  48.29°

Explanation:

Given the data in the question and the diagram below,

First we work on the force on the left hand side.

Left Horizontal

F_{LH = βgAr

here, h = 3/2 = 1.5 m, β = 1.6, g = 9.81 m/s², A = 3 m × 6 m = 18 m²

we substitute

F_{LH = βgAh = ( 1.6 × 1000 ) × 9.81 × 18 × 1.5 = 423792 N

Left Vertical

F_{LV = ( βgπh² / 2 ) × W

we substitute

F_{LV = [ ( ( 1.6 × 1000 ) × 9.81  × π(1.5)² ) / 2 ] × 6 = 332845.458 N

Now we go to the right hand side

Right Horizontal

F_{RH = βgAh

here, h' = 1.5/2 = 0.75 m, β = 0.8, g = 9.81 m/s², A = 1.5 m × 6 m = 9 m²

we substitute

F_{RH = ( 0.8 × 1000 ) × 9.81 × 9 × 0.75 ) = 52974 N

Right Vertical

F_{RV = ( βgπh² / 4 ) × W

we substitute

F_{RV = [ ( ( 0.8 × 1000 ) × 9.81  × π(1.5)² ) / 4 ] × 6 =  83211.36 N

Hence

Fx = F_{LH - F_{RH = 52974 N - 423792 N =  370818 N

Fy = F_{LV + F_{RV = 332845.458 N + 83211.36 N = 416056.818 N

R = √( Fx² + Fy² ) = √[ (370818 N)² + (416056.818 N)² ] = 557323.3 N

R = 557.32 kN

Therefore, the magnitude of the resultant force is 557.32 kN

Direction of resultant force;

tanθ = Fy / Fx

we substitute

tanθ = 416056.818 N / 370818 N

tanθ = 1.121997

θ = tan⁻¹( 1.121997 )

θ = 48.29°

Therefore, the direction of resultant force is  48.29°

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