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Nady [450]
3 years ago
13

Please help. Basic. Brainliest will be given.

Physics
2 answers:
Natali [406]3 years ago
7 0

Answer:

Distance of displacement = 28.71 m

Angle of displacement = 46.91 degrees

Explanation:

convert all individual displacements to simple vectors.

6m east  -> <6,0>

25m at 57 -> <25cos57, 25sin57>

Total displacement = sum of two vectors

= <6+25cos57, 0+25sin57>

=<19.62, 20.97>

Magnitude of displacement

= sqrt(19.62^2+20.97^2)

= 28.71

Direction of displacement

= atan2(20.97,19.62)

= 46.91 degrees

kkurt [141]3 years ago
6 0

Answer:

28.7 m at 46.9°

Explanation:

The x component of the displacement is:

x = 6 m cos 0° + 25 m cos 57°

x = 19.6 m

The y component of the displacement is:

y = 6 m sin 0° + 25 m sin 57°

y = 21.0 m

The total displacement is found with Pythagorean theorem:

d = √(x² + y²)

d = 28.7 m

And the direction is found with trig:

θ = tan⁻¹(y/x)

θ = 46.9°

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The energy associated with an object's motion is called kinetic energy. ... This is also called thermal energy – the greater the thermal energy, the greater the kinetic energy of atomic motion, and vice versa.

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3 years ago
Explain which planets have seasons and why some planets have none at all.
Sergeu [11.5K]

Answer:

Some planets have seasons some don't bc of the distance from the sun some of them are too cold or too hot to have seasons

8 0
3 years ago
I need help with these Physics problems​
adoni [48]

Answer:

1. 3 m

2. 27 s

Explanation:

1. "A car traveling at +33 m/s sees a red light and has to stop.  If the driver can accelerate at -5.5 m/s², how far does it travel?"

Given:

v₀ = 33 m/s

v = 0 m/s

a = -5.5 m/s²

Unknown: Δx

To determine the equation you need, look for which variable you don't have and aren't solving for.  In this case, we aren't given time and aren't solving for time.  So look for an equation that doesn't have t in it.

Equation: v² = v₀² + 2aΔx

Substitute and solve:

(0 m/s)² = (33 m/s)² + 2(-5.5 m/s²) Δx

Δx = 3 m

2. "A plane starting from rest at one end of a runway accelerates at 4.8 m/s² for 1800 m.  How long did it take to accelerate?"

Given:

v₀ = 0 m/s

a = 4.8 m/s²

Δx = 1800 m

Unknown: t

Equation: Δx = v₀ t + ½ a t²

Substitute and solve:

1800 m = (0 m/s) t + ½ (4.8 m/s²) t²

t ≈ 27 s

4 0
3 years ago
A sheet of metal is 2mm wide 10cm tall and 15cm long. it was 4g. what is the density? <br>​
Hoochie [10]

Answer:

Ro = 133 [kg/m³]

Explanation:

In order to solve this problem, we must apply the definition of density, which is defined as the relationship between mass and volume.

Ro = m/V

where:

m = mass [kg]

V = volume [m³]

We will convert the units of length to meters and the mass to kilograms.

L = 15 [cm] = 0.15 [m]

t = 2 [mm] = 0.002 [m]

w = 10 [cm] = 0.1 [m]

Now we can find the volume.

V = 0.15*0.002*0.1\\V = 0.00003 [m^{3} ]

And the mass m = 4 [gramm] = 0.004 [kg]

Ro = 0.004/0.00003\\Ro = 133 [kg/m^{3}]

3 0
3 years ago
A train traveling at 6.4 m/s accelerates at 0.10 m/s 2 over a distance of 100 m. How large is the train’s final velocity?
klasskru [66]

The final velocity of the train at the end of the given distance is 7.81 m/s.

The given parameters;

  • initial velocity of the train, u = 6.4 m/s
  • acceleration of the train, a = 0.1 m/s²
  • distance traveled, s = 100 m

The final velocity of the train at the end of the given distance is calculated using the following kinematic equation;

v² = u² + 2as

v² = (6.4)² + (2 x 0.1 x 100)

v² = 60.96

v = √60.96

v = 7.81 m/s

Thus, the final velocity of the train at the end of the given distance is 7.81 m/s.

Learn more here:brainly.com/question/21180604

4 0
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