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erik [133]
3 years ago
6

If a golf ball and a ping-pong ball both move with the same kinetic energy, which has the greater speed? 1. the golf ball 2. can

not be determined 3. the ping-pong ball 4. the two balls have the same speed.
Physics
1 answer:
schepotkina [342]3 years ago
4 0
Think about it like this, the more mass there is, the faster its going to go. If you took a golf ball and a ping pong ball and you held them each separately, you would notice that the golf ball is heavier. If they move with the same kinetic energy, but the golf ball WEIGHS more, then the golf ball will have the greater speed. If you think about it, the ping pong ball may be taking its time to get to wherever its going. 
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A light, a heater, and a hair dryer were all running in the bathroom at the same time. Suddenly, they all turn off. After all, t
Ratling [72]
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3 0
3 years ago
After enjoying a tasty meal of the first moth, the bat goes after another moth. Flying with the same speed and emitting the same
Aleksandr-060686 [28]

This question is incomplete, the complete question is;

A bat flies towards a moth at 7.1 m/s while the moth is flying towards the bat at 4.4 m/s. The bat emits a sound wave of 51.7 kHz.

After enjoying a tasty meal of the first moth, the bat goes after another moth. Flying with the same speed and emitting the same frequency, this time the bat detects a reflected frequency of 55.5 kHz. How fast is the second moth moving

Answer:

the second moth is moving at 5.062 m/s

Explanation:

Given the data in the question;

Using doppler's effect

f_{moth = f₀( v_{s ± v_{observer / v_{s ± v_{source )

f₁ = f₀( (v_{s + v₂) / ( v_{s - v₁ ) )

frequency reflected from the moth,

Now, moth is the source and the bat is the receiver

f₂ = f₁( (v_{s + v₁ ) / ( v_{s - v₂ ) )

hence, f = f₀[ ( ( v_{s + v₁ ) / ( v_{s - v₂ ) ) ( ( v_{s + u₂ ) / ( v_{s - u₁ ) )

we know that, the velocity of sound v_{s = 343 m/s.

given that v₁ and v₂ { velocity of bat } = 7.1 m/s, f₀ = 51.7 kHz and f = 55.5 kHz.

we substitute

55.5 = 51.7[ ( ( 343 + 7.1 ) / ( 343 - 7.1 ) ) ( ( 343 + u ) / ( 343 - u ) ) ]

55.5 = 51.7[  ( 350.1 / 335.9 ) ( ( 343 + u ) / ( 343 - u ) ) ]

55.5 = 51.7[ 1.04227 ( ( 343 + u ) / ( 343 - u ) ) ]

55.5 = 53.885359 ( ( 343 + u ) / ( 343 - u ) ) ]

55.5 / 53.885359 = ( 343 + u ) / ( 343 - u )

1.02996 =  ( 343 + u₂ ) / ( 343 - u )

( 343 + u₂ ) = 1.02996( 343 - u )

343 + u = 353.27628 - 1.02996u

u + 1.02996u = 353.27628 - 343

2.02996u = 10.27628

u = 10.27628 / 2.02996

u = 5.062 m/s

Therefore, the second moth is moving at 5.062 m/s

4 0
3 years ago
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