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3 years ago

13

If you are driving 95 km/h along a straight road and you look to the side for 2.0s, how far do you travel during this inattentiv

e period

1 answer:

Bad White [126]3 years ago

3 0

95km/h
95km/60*60sec
(95/(60*30))km/2sec
0.05277km

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A rigid dam is composed of material of SG = 5 . The dam height is 20 m . What is the minimum thickness b of the dam necessary to

Kay [80]

Answer:

b = 5.164 m is the minimum thickness of the dam

Explanation:

Given

SG = 5

h = 20 m

b = ?

w = 1 m

γw = 9800 N/m³

We can get the forces as follows

Fp = γw*(h/2)*(h*w)

⇒ Fp = (9800 N/m³)*(20 m/2)*(20 m*1 m) = 1.96*10⁶N

W = (SG*γw)*(h*b*w)

⇒ W = (5*9800 N/m³)*(20 m*b*1 m) = (9.8*10⁵N/m)*b

Then, we apply

∑M₀ = 0 (counterclockwise)

- Fp*(h/3) + W*(b/2) = 0

⇒ - 1.96*10⁶N*(20 m/3) + (9.8*10⁵N/m)*b*(b/2) = 0

- 13.066*10⁶N-m + (4.9*10⁵N/m)*b² = 0

⇒ b = 5.164 m is the minimum thickness of the dam

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3 years ago

The force of repulsion that two like charges exert on each other 5N. what will be if the distance between the charge is decrease

GalinKa [24]

The new force becomes One Ninth (1/9) of the original force.

The force between two point charges (let's say $\mathrm{Q} 1$ and $\mathrm{Q} 2$$ ) is given by the following formula:

Force $=k \times Q 1 \times Q 2$ divided by ( $r$ squared)

Here r is the distance.

If we multiply r by three then after squaring it will become $9 \times r$ squared.

Let's rewrite the formula and call it new Force:

New Force $=\mathrm{K} \times \mathrm{Q} 1 \times \mathrm{Q} 2$ divided by $(9 \times \mathrm{r}$ squared )

Now just separate the 9 :

New Force $=1 / 9(\mathrm{~K} \times \mathrm{Q} 1 \times \mathrm{Q} 2$ divided by $(\mathrm{r}$ Squared ))

New Force $=1 / 9$ (Force)

So turns out that the new force becomes One Ninth (1/9) of the original force.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to define force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Learn more about force brainly.com/question/13191643

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1 year ago

Define Velocity with an example

kolbaska11 [484]

Velocity stands for Displacement w.r.t time

$\\ \bull\tt\longmapsto Velocity=\dfrac{Displacement}{Time}$

Or

$\\ \bull\tt\longmapsto v=\dfrac{ds}{dt}$

It has units m/s.

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2 years ago

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Suppose earth's mass increased but earth's diameter didn't change. Describe how the gravitational force between Earth and the ob

zheka24 [161]

Answer:

It increases proportionally

Explanation:

The gravitational force between the Earth and an object on its surface is given by

$F=G\frac{Mm}{R^2}$

where

G is the gravitational constant

M is the Earth's mass

m is the mass of the object

R is the Earth's radius

In this problem, the Earth's mass is increased, while the diameter (and therefore, the radius) doesn't change. From the equation, we see that the gravitational force is directly proportional to the Earth's mass: therefore, if the mass is increased, the force will increase as well by the same proportion (for example, if the mass is doubled, the force will double as well)

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Sports managers have the potential to earn more than a million dollars per year.<br> True<br> false

andriy [413]

Answer:

true

Explanation:

hope this helped!

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2 years ago