Answer:
1.40 m/s^2
Explanation:
Given data
Velocity= 17.4 m/s
time= 12.4 seconds
We want to find the acceleration of the rock
We know that
acceleration = velocity/time
Substitute
acceleration= 17.4/12.4
acceleration=1.40 m/s^2
Hence the acceleration is 1.40 m/s^2
Positively charged protons in the nucleus of the gold atom .... rutherford scattering ???
Answer:
Explanation:The rotational inertia of any object depends directly on the distance the mass is from the axis of a rotating object
Having more mass at the sides will increase the rotational inertia of the object that is why a Hollow sphere having same M and R as the solid one has more rotational inertia as it has more mass at the sides.
The sphere have some mass at the center but most of its mass is closer to its radius and thus have more inertia than flat Disk.
The same relation exist between a flat disk and hollow sphere. The hollow sphere have some mass at the center but most of its mass is closer to its radius and thus have more inertia.
The rotational of the objects can be calculated by these equations
![FlatDisk=\frac{1}{4} MR^2\\Sphere=\frac{2}{5} MR^2\\HollowSphere=\frac{2}{3} MR^2\\](https://tex.z-dn.net/?f=FlatDisk%3D%5Cfrac%7B1%7D%7B4%7D%20MR%5E2%5C%5CSphere%3D%5Cfrac%7B2%7D%7B5%7D%20MR%5E2%5C%5CHollowSphere%3D%5Cfrac%7B2%7D%7B3%7D%20MR%5E2%5C%5C)
Answer:
the ball experiences the greater momentum change
Explanation:
You have to take into account that momentum change is given by
![\Delta p=mv_f-mv_b](https://tex.z-dn.net/?f=%5CDelta%20p%3Dmv_f-mv_b)
where vf and vb are the speed of the object after and before the impact.
In the case of the ball you have
![\Delta p=(0.05kg)(-10.0\frac{m}{s})-(0.05kg)(10.0\frac{m}{s})=-1kg\frac{m}{s}](https://tex.z-dn.net/?f=%5CDelta%20p%3D%280.05kg%29%28-10.0%5Cfrac%7Bm%7D%7Bs%7D%29-%280.05kg%29%2810.0%5Cfrac%7Bm%7D%7Bs%7D%29%3D-1kg%5Cfrac%7Bm%7D%7Bs%7D)
where the minus of vf is included due to the motion is in an opposite direction regarding with vb
And for the lump
![\Delta p=(0.05kg)(10.0\frac{m}{s})-(0.05kg)(0\frac{m}{s})=0.5kg\frac{m}{s}](https://tex.z-dn.net/?f=%5CDelta%20p%3D%280.05kg%29%2810.0%5Cfrac%7Bm%7D%7Bs%7D%29-%280.05kg%29%280%5Cfrac%7Bm%7D%7Bs%7D%29%3D0.5kg%5Cfrac%7Bm%7D%7Bs%7D)
Hence, the ball experiences the greater change
hope this helps!!