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denis-greek [22]
3 years ago
12

when a substance such as ice melts, its temperature increases. desrcibe what happens to the arrangment of water molecules as the

temperature increases
Physics
1 answer:
trasher [3.6K]3 years ago
7 0

Explanation:

The water molecules begins to leave their fixed position and begins to move as the temperature increases.

When ice melts, it undergoes a state change from solid to liquid and with increasing temperature becomes a gas.

  • The basis for this is the increasing movement of the molecules of the water as it transitions from one phase to another.
  • In the ice, the molecules are locked and fixed in the lattice
  • As the temperature increases, the average kinetic energy of the particles rises.
  • This makes the structure of the ice to collapse and forms liquids.
  • By the virtue of this, they flow and move over one another
  • With increasing temperature, the bonds are broken and vapor forms
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What is time taken by the stone ?
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The time taken by the stone to hit the ground would be 5.12 seconds.

<h3>What are the three equations of motion?</h3>

There are three equations of motion given by  Newton

The first equation is given as follows

v = u + at

the second equation is given as follows

S = ut + 1/2×a×t²

the third equation is given as follows

v² - u² = 2×a×s

Keep in mind that these calculations only apply to uniform acceleration.

As given in the problem, a stone is dropped from the helicopter which is ascending at the speed of 19.6 m/s

height(S) = 156.8 meters

initial velocity(u) = -19.6 m/s

acceleration(a) = 9.81 m/s²

By using the second equation of motion given by newton

S = ut + 1/2at²

S = 156.8m ,u= -19.6 m/s , a= 9.81 m/s² and t =? seconds

156.8= -19.6t + 9.81t²

t = 5.12 seconds

Thus, the time taken by the stone to hit the ground would be 5.12 seconds.

Learn more about equations of motion from here,

brainly.com/question/5955789

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2 years ago
I need help with this Physics problem. I've been stuck forever:
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3 years ago
A ball is dropped from rest and falls to the floor. The initial gravitational potential energy of the ball-Earth-floor system is
Cloud [144]

Answer:

The mechanical energy of the ball-Earth-floor system the instant the ball left the floor is 7 Joules.

Explanation:

It is given that,

Initial gravitational potential energy of the ball-Earth-floor system is 10 J.

The ball then bounces back up to a height where the gravitational potential energy is 7 J.

Let U is the mechanical energy of the ball-Earth-floor system the instant the ball left the floor. Due to the conservation of energy, the mechanical energy is equal to difference between initial gravitational potential energy and the after bouncing back up to a height.

Initial mechanical energy is 10 + 0 = 10 J

Mechanical energy just before the collision is 0 + 10 = 10 J

Final mechanical energy, 7 + 0 = 7 J

Hence, the mechanical energy of the ball-Earth-floor system the instant the ball left the floor is 7 Joules.

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An object's position in a given coordinate system is described by the vector r = t2 i - (3t + 3) j. Assume the object moves with
Ipatiy [6.2K]

Answer:

The object´s displacement vector is Δr =  8i - 6 j  

Explanation:

Hi there!

The position vector is given by the following function:

r = t²i - (3t + 3) j

Let´s find the position of the object at time t1 and t2:

At t1 = 1 s:

r1 = (1)² i - (3 · (1) + 3 )j

r1 = 1 i - 6 j

At t2 = 3 s:

r2 = (3)² i - (3 · (3) + 3) j

r2 = 9 i - 12 j

The displacement is calculated as follows:

displacement = Δr = final position - initial position = r2 - r1

r2 - r1 = 9 i - 12 j - (1 i - 6 j)

r2 - r1 = 9 i - 12 j - 1 i + 6 j

r2 - r1 = 8 i - 6 j

The object´s displacement vector is Δr =  8i - 6 j  

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