Hi there!
We can use the following kinematic equation:
vf = final velocity (? m/s)
vi = intial velocity (0 m/s)
a = acceleration (5 m/s²)
d = displacement (8 m)
Plug in the givens and solve.
Answer:
ffcvghnvb vyhgyhvthbgvgybn ytvg dfvthgbhtfgybhvtgbyhnt vfyhn fgb fvb
Explanation:
Answer:
The wavelength of the radiation absorbed by ozone is 319.83 nm
Explanation:
Given;
frequency of absorbed ultraviolet (UV) radiation, f = 9.38×10¹⁴ Hz
speed of the absorbed ultraviolet (UV) radiation, equals speed of light, v = 3 x 10⁸ m/s
wavelength of the absorbed ultraviolet (UV) radiation, λ = ?
Apply wave equation for speed, frequency and wavelength;
v = fλ
λ = v / f
λ = (3 x 10⁸) / (9.38×10¹⁴)
λ = 3.1983 x 10⁻⁷ m
λ = 319.83 x 10⁻⁹ m
λ = 319.83 nm
Therefore, the wavelength of the radiation absorbed by ozone is 319.83 nm
Answer:
" In the Balmer series, the transitions happening in visible range are considered, which range from around 400 nm to 700 nm. The longest wavelength visible in the Balmer series is 656 nm."
Explanation:
Hope this is helpful :)
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