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Amiraneli [1.4K]

3 years ago

6

Sound pulses emitted by a dolphin travel through 20°c ocean water at a rate of 1450 m/s. in 20°c air, these pulses would travel

342.9 m/s. how can you account for this difference in speed?

1 answer:

12345 [234]3 years ago

7 0

The difference in speed is due to the different densities of the two mediums.

In fact, the higher the density of the medium, the greater the speed of sound. Sound travels faster in liquids (e.g. water) than in gases (e.g. air) because liquids are more dense than gases. This is due to the fact that in liquids, molecules are closer to each other, and since sound is essemptially vibration of molecules, these vibrations are transmitted faster from molecule to molecule in a more dense medium (such as a liquid) rather than in a less dense medium (such as a gas)

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An inductor carries a current of 1.6 a, and the magnetic energy stored in the inductor is 0.0020 j. what is the inductance

faltersainse [42]

Energy stored= Li^2/2
Therefore L=2(E.S)/i^2
= 0.0013

8 0

3 years ago

One Affective way to develop the feeling function in one’s personality is to

Mademuasel [1]

Answer:

A.

Explanation:

I think it’s a. Because, I normally think about how someone else feels if I want to say something.

5 0

2 years ago

Students were asked to place a mint in their mouths and determine how long it took for the mint to dissolve. The condition of th

Llana [10]

Students were asked to place a mint in their mouths and determine how long it took for the mint to dissolve. The condition of the mint varied in each student group. One group of students were asked to leave a whole mint in their mouth, not moving it around, and let it dissolve. Another group swirled a mint, while the other groups used mints broken into smaller pieces. See the chart for all of the manipulated variable. After reviewing that data table, what kind of result would you predict for the swirled, whole mint?

A) The time is likely between 10-30 seconds.

B) The time is likely between 40-80 seconds.

C) The time is likely between 90-160 seconds.

D) The time is likely between 100-200 seconds.

ANSWER: B) The time is likely between 40-80 seconds.

EXPLANATION:The time is likely between 40-80 seconds.

By swirling the mint, this is agitating and creating a higher frequency of collisions between the saliva particles and mint particles, increasing the rate of dissolution. Therefore, the time is likely to be less than the mint cut in half but probably more than the mint when it is in small pieces.

7 0

4 years ago

Read 2 more answers

Charge q1 = +2.00 μC is at -0.500 m along the x axis. Charge q2 = -2.00 μC is at 0.500 m along the x axis. Charge q3 = 2.00 μC i

Kobotan [32]

The magnitude of <em>electrical</em> force on charge $q_{3}$ due to the others is 0.102 newtons.

<h3>How to calculate the electrical force experimented on a particle</h3>

The vector <em>position</em> of each particle respect to origin are described below:

$\vec r_{1} = (-0.500, 0)\,[m]$

$\vec r_{2} = (+0.500, 0)\,[m]$

$\vec r_{3} = (0, +0.500)\,[m]$

Then, distances of the former two particles particles respect to the latter one are found now:

$\vec r_{13} = (+0.500, +0.500)\,[m]$

$r_{13} = \sqrt{\vec r_{13}\,\bullet\,\vec r_{13}} = \sqrt{(0.500\,m)^{2}+(0.500\,m)^{2}}$

$r_{13} =\frac{\sqrt{2}}{2}\,m$

$\vec r_{23} = (-0.500, +0.500)\,[m]$

$r_{23} = \sqrt{\vec r_{23}\,\bullet \,\vec r_{23}} = \sqrt{(-0.500\,m)^{2}+(0.500\,m)^{2}}$

$r_{23} =\frac{\sqrt{2}}{2}\,m$

The resultant force is found by Coulomb's law and principle of superposition:

$\vec R = \vec F_{13}+\vec F_{23}$ (1)

Please notice that particles with charges of <em>same</em> sign attract each other and particles with charges of <em>opposite</em> sign repeal each other.

$\vec R = \frac{k\cdot q_{1}\cdot q_{3}}{r_{13}^{2}}\cdot \vec u_{13} +\frac{k\cdot q_{2}\cdot q_{3}}{r_{23}^{2}}\cdot \vec u_{23}$ (2)

Where:

$k$ - Electrostatic constant, in newton-square meters per square Coulomb.
$q_{1}$ , $q_{2}$ , $q_{3}$ - Electric charges, in Coulombs.
$r_{13}$ , $r_{23}$ - Distances between particles, in meters.
$\vec u_{13}$ , $\vec u_{23}$ - Unit vectors, no unit.

If we know that $k = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}$ , $q_{1} = 2\times 10^{-6}\,C$ , $q_{2} = 2\times 10^{-6}\,C$ , $q_{3} = 2\times 10^{-6}\,C$ , $r_{13} =\frac{\sqrt{2}}{2}\,m$ , $r_{23} =\frac{\sqrt{2}}{2}\,m$ , $\vec u_{13} = \left(-\frac{\sqrt{2}}{2}, - \frac{\sqrt{2}}{2} \right)$ and $\vec u_{23} = \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)$ , then the vector force on charge $q_{3}$ is:

$\vec R = \frac{\left(8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot (2\times 10^{-6}\,C)\cdot (2\times 10^{-6}\,C)}{\left(\frac{\sqrt{2}}{2}\,m \right)^{2}} \cdot \left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right) + \frac{\left(8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot (2\times 10^{-6}\,C)\cdot (2\times 10^{-6}\,C)}{\left(\frac{\sqrt{2}}{2}\,m \right)^{2}} \cdot \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)$

$\vec R = 0.072\cdot \left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right) + 0.072\cdot \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)\,[N]$

$\vec R = 0.072\cdot \left(0, -\sqrt{2}\right)\,[N]$

And the magnitude of the <em>electrical</em> force on charge $q_{3}$ ( $R$ ), in newtons, due to the others is found by Pythagorean theorem:

$R = 0.102\,N$

The magnitude of <em>electrical</em> force on charge $q_{3}$ due to the others is 0.102 newtons. $\blacksquare$

To learn more on Coulomb's law, we kindly invite to check this verified question: brainly.com/question/506926

8 0

2 years ago

What is the reversal experienced by an image formed in a plane mirror called?

algol [13]

Answer:

Lateral Inversion

Explanation:

lateral inversion simply means the change around of the image of an object from side to side

The image of an object formed by a plane mirror is laterally inverted.

5 0

3 years ago