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OlgaM077 [116]
3 years ago
14

what does it mean when the h3o+ to x- distance doesn't change much as the first 4 to 5 water molecules are added

Chemistry
2 answers:
podryga [215]3 years ago
7 0
If X is an equivalent base to H₂O
HX is an equivalent acid to H₃O⁺
HX is a stronger acid than H₃O⁺
HX is not an acid
X⁻ is a stronger base than H₂O
HX is a weaker acid than H₃O⁺
X⁻ is a weaker base than H₂O
X⁻ is not a base.

The correct response or this is 
X⁻ is a stronger base than H₂O
HX is a weaker acid than H₃O⁺
algol [13]3 years ago
6 0

Gjvdigcyivcghjnjjxhfbhdbdbbxbfbdbbbfbdbbdhdbbdbdbxbxbbcbcbbxbxbxbbxbdbbcbdbdbdbhdbfbcbbcbfbdbbcbbcbxbbxbcbcbbcbbxbxbbxbbxbxbbdbdbcbbdbbdbbxbbxbbxbbfbfbxbdbbdbdbdbbxbbfbbfbfbfbbfbfbccbbcbcbbcbxbxbbxbx

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Calculate the mass percent by volume of 330.1 g of glucose (C₆H₁₂O₆, MM = 180.2 g/mol) in 325 mL of solution.
nadezda [96]

Answer: The mass percent by volume is 101.6%

Explanation:

The solution concentration expressed in percent by volume means that the amount of solute present in 100 parts volume of solution.

It is represented in formula as :

mass percent by volume =\frac{\text {mass of solute}\times 100}{\text {Volume of solution in ml}}\%

Given : mass of glucose = 330.1 g

volume of solution = 325 ml

Thus mass percent by volume =\frac{330.1g\times 100}{325ml}=101.6\%

Thus the mass percent by volume is 101.6%

3 0
3 years ago
In Perugino's Christ Delivering the Keys of the Kingdom to St. Peter, the artist reminds the viewer of the link between Constant
Leona [35]

Answer:

Is an exemplar of Italian Renaissance painting.

Explanation:

the Kingdom to St. Peter is an exemplar of Italian Renaissance painting. The work was part of a large decorative program commissioned by Pope Sixtus IV in 1481 for the walls of the Sistine Chapel (the name “Sistine” being derived from Sixtus’ own name), which was then, as it is today, the pope’s private chapel in the Vatican, in Rome.

6 0
3 years ago
Name two solid liquid and gaseous element at the normal temperature and normal press<br>ure​
liubo4ka [24]

Answer:

Solid: calcium and potassium

Liquid: mercury and bromine

Gaseous: oxygen and fluorine

Explanation:

Matter exists in three different states namely: solid, gaseous and liquid. Elements that are found in nature are classified as matter. Since, these elements are grouped as matter, they can either be found as either solids, liquids or gases at normal temperature and pressure.

At normal temperature (20°C or 293K) and pressure (1 atm), the following elements are found to exists in the respective state of matter:

Solid: Calcium (Ca) and potassium (K)

Liquid: Mercury (Hg) and bromine (Br)

Gaseous: Oxygen (O) and fluorine (F)

7 0
3 years ago
You want to sweeten a cup of tea, and you have three types of sugar: sugar cubes (volume: 5ml), granulated sugar (volume: 0.1 ml
sp2606 [1]

Answer:

powdered sugar

Explanation:

The higher is the exposed area of sugar, the faster is the dissolution process. Thus, to choose between the different types of sugar, we have to look at the volume occupied by the sugar.

In sugar cubes, the particles of sugar as compacted in a cube, so the particles inside the cube are not exposed to the solvent (water). So, sugar cubes have the slowest dissolution process. Then, in granulated sugar, the particles have more area exposed, so this type of sugar will dissolve faster than sugar cubes. Finally, powdered sugar is composed of tiny particles with more are exposed, so powdered sugar has the fastest dissolution process.

Therefore, powdered sugar will dissolve the fastest.

4 0
3 years ago
At a certain temperature the equilibrium constant, Kc, equals 0.11 for the reaction:
Butoxors [25]

<u>Answer:</u> The equilibrium concentration of ICl is 0.27 M

<u>Explanation:</u>

We are given:

Initial moles of iodine gas = 0.45 moles

Initial moles of chlorine gas = 0.45 moles

Volume of the flask = 2.0 L

The molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume}}

Initial concentration of iodine gas = \frac{0.45}{2}=0.225M

Initial concentration of chlorine gas = \frac{0.45}{2}=0.225M

For the given chemical equation:

2ICl(g)\rightarrow I_2(g)+Cl_2(g);K_c=0.11

As, the initial moles of iodine and chlorine are given. So, the reaction will proceed backwards.

The chemical equation becomes:

                      I_2(g)+Cl_2(g)\rightarrow 2ICl(g);K_c=\frac{1}{0.11}=9.091

<u>Initial:</u>         0.225      0.225

<u>At eqllm:</u>   0.225-x    0.225-x     2x

The expression of K_c for above equation follows:

K_c=\frac{[ICl]^2}{[Cl_2][I_2]}

Putting values in above equation, we get:

9.091=\frac{(2x)^2}{(0.225-x)\times (0.225-x)}\\\\x=0.135,0.668

Neglecting the value of x = 0.668 because equilibrium concentration cannot be greater than the initial concentration

So, equilibrium concentration of ICl = 2x = (2 × 0.135) = 0.27 M

Hence, the equilibrium concentration of ICl is 0.27 M

6 0
3 years ago
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