Weight percentage of nitrogen can be calculated using the following rule:
weight percentage of nitrogen = (weight of nitrogen / weight of urea) x 100

From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of nitrogen = 14 grams
molecular mass of hydrogen = 1 grams
molecular mass of oxygen = 16 grams

therefore:
mass of nitrogen in urea = 2(14) = 28 grams
mass of urea = 12 + 2(14) + 4(1) + 16 = 60 grams

Substitute with the masses in the equation to get the percentage:
weight percentage of nitrogen = (28/60) x 100 = 46.667%

7 0

4 years ago

When the reaction 3 no(g) → n2o(g) + no2(g) is proceeding under conditions such that 0.015 mol/l of n2o is being formed each sec

netineya [11]

Answer:

1) The rate of the overall reaction = Δ[N₂O]/Δt = 0.015 mol/L.s.

2) The rate of change for NO = - Δ[NO]/Δt = 3 Δ[N₂O]/Δt = 0.045 mol/L.s.

Explanation:

For the reaction:

3NO(g) → N₂O(g) + NO₂(g).

The rate of the reaction = -1/3 Δ[NO]/Δt = Δ[N₂O]/Δt = Δ[NO₂]/Δt.

Given that: Δ[N₂O]/Δt = 0.015 mol/L.s.

1) The rate of the overall reaction is?

The rate of the overall reaction = Δ[N₂O]/Δt = 0.015 mol/L.s.

2) The rate of change for NO is?

The rate of change for NO = - Δ[NO]/Δt.

∵ -1/3 Δ[NO]/Δt = Δ[N₂O]/Δt.

∴ The rate of change for NO = - Δ[NO]/Δt = 3 Δ[N₂O]/Δt = 3(0.015 mol/L.s) = 0.045 mol/L.s.

7 0

3 years ago