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3 years ago

1. Alpha emission by a radium-226 nucleus

Chemistry

1 answer:

statuscvo [17]3 years ago

8 0

Answer:

₈₈Ra²²⁶ → ₈₆Rn²²² + ₂He⁴ + energy

Explanation:

Alpha beta and gamma radiations are the examples of ionizing radiations.

Alpha radiations are emitted as a result of radioactive decay. The atom emit the alpha particles having two proton and two neutrons. It is also called helium nuclei. When atom undergoes the alpha emission the original atom convert into the atom having mass number less than 4 and atomic number less than 2 as compared to parent atom.

For example:

₈₈Ra²²⁶ → ₈₆Rn²²² + ₂He⁴ + energy

Properties of alpha radiation:

Alpha radiations can travel in a short distance.

These radiations can not penetrate into the skin or clothes.

These radiations can be harmful for the human if these are inhaled.

These radiations can be stopped by a piece of paper.

Another example:

₉₂U²³⁸ → ₉₀Th²³⁴ + ₂He⁴ + energy

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1. Calculate the momentum of a 1,500 kg car traveling at 6 m/s.

ziro4ka [17]

Answer:

1. $9000kgm/s$

2. $258,000kgm/s$

Explanation:

1.Momentum is given as the product of mass by velocity of an object.

Momentum, $p=mv$

m=1,500kh, v=6m/s

$p=1500*6\\p=9000kgm/s$

2.Momentum, $p=mv$

m=7800kg, v=30m/s

$p_1=7800*30\\p_1=234,000kgm/s\\$

new mass=7800+800=8600

As mass is increased, so does the resultant velocity as mass is directly proportional to velocity.

$p_2=8600*30\\p_2=258,000kgm/s$

8 0

4 years ago

The side chains of amino acids may contain..

salantis [7]

The correct answer is d)all of above

examples for a are tyrosine for b lysine and for c isoleucine

6 0

3 years ago

Read 2 more answers

Some SbCl5 is allowed to dissociate into SbCl3 and Cl2 at 521 K. At equilibrium, [SbCl5] = 0.195 M, and [SbCl3] = [Cl2] = 6.98×1

Brilliant_brown [7]

Answer:

a) The equilibrium will shift in the right direction.

b) The new equilibrium concentrations after reestablishment of the equilibrium :

$[SbCl_5]=(0.370-x) M=(0.370-0.0233) M=0.3467 M$

$[SbCl_3]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M$

$[Cl_2]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M$

Explanation:

$SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)$

a) Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

On increase in amount of reactant

$SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)$

If the reactant is increased, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where more product formation is taking place. As the number of moles of $SbCl_5$ is increasing .So, the equilibrium will shift in the right direction.

$SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)$

Concentration of $SbCl_5$ = 0.195 M

Concentration of $SbCl_3$ = $6.98\times 10^{-2} M$

Concentration of $Cl_2$ = $6.98\times 10^{-2} M$

On adding more $[SbCl_5$ to 0.370 M at equilibrium :

$SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)$

Initially

0.370 M $6.98\times 10^{-2}M$

At equilibrium:

(0.370-x)M $(6.98\times 10^{-2}+x)M$

The equilibrium constant of the reaction = $K_c$

$K_c=2.50\times 10^{-2}$

The equilibrium expression is given as:

$K_c=\frac{[SbCl_3][Cl_2]}{[SbCl_5]}$

$2.50\times 10^{-2}=\frac{(6.98\times 10^{-2}+x)M\times (6.98\times 10^{-2}+x)M}{(0.370-x) M}$

On solving for x:

x = 0.0233 M

The new equilibrium concentrations after reestablishment of the equilibrium :

$[SbCl_5]=(0.370-x) M=(0.370-0.0233) M=0.3467 M$

$[SbCl_3]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M$

$[Cl_2]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M$

3 0

4 years ago

Anions are formed when *

soldier1979 [14.2K]

Anions are negative ions so it’s when an atom gains electrons

6 0

3 years ago

What did Dalton’s atomic theory teach

sweet-ann [11.9K]

Answer:

All matter is composed of atoms.

Atoms are not destructible.

Compounds formation occur by the combination of one or different types of atoms

In the chemical reactions, atoms are rearranged.

The atom of the same elements are similar in size and properties and the Atoms of the different elements are different in size and properties.

Explanation:

<u>John Dalton has developed the Dalton atomic theory.</u>

Dalton atomic theory was the first to explain that all matters composed of atoms and its properties, the atom as the smallest particle which cannot be destroyed and damaged.

This theory was based on the <u>law of conservation of mass and law of constant composition.</u>

His theory was accepted by many scientists.

6 0

4 years ago

Read 2 more answers