<span>0.0165 m
The balanced equation for the reaction is
AgNO3 + MgCl2 ==> AgCl + Mg(NO3)2
So it's obvious that for each Mg ion, you'll get 1 AgCl molecule as a product. Now calculate the molar mass of AgCl, starting with looking up the atomic weights.
Atomic weight silver = 107.8682
Atomic weight chlorine = 35.453
Molar mass AgCl = 107.8682 + 35.453 = 143.3212 g/mol
Now how many moles were produced?
0.1183 g / 143.3212 g/mol = 0.000825419 mol
So we had 0.000825419 moles of MgCl2 in the sample of 50.0 ml. Since concentration is defined as moles per liter, do the division.
0.000825419 / 0.0500 = 0.016508374 mol/L = 0.016508374 m
Rounding to 3 significant figures gives 0.0165 m</span>
Answer:
Sodium bicarbonate
Explanation:
Sodium bicarbonate ( NaHCO₃ ) -
Sodium bicarbonate , according to the IUPAC nomenclature , its name is sodium hydrogen carbonate ,and in common terms also refereed to as baking soda .
It is a white crystalline solid , it is basic in nature .
<u>The cation and anion of this salt are the sodium ion ( Na⁺) and the anion bicarbonate anion (HCO³⁻) .</u>
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This can be solved using Dalton's Law of Partial pressures. This law states that the total pressure exerted by a gas mixture is equal to the sum of the partial pressure of each gas in the mixture as if it exist alone in a container. In order to solve, we need the partial pressures of the gases given. Calculations are as follows:
P = P1 + P2 + P3
P = (82.0575 atm.cm^3/mol.K)( 298.15 K)/1.50 x 10^3 cm^3) x (<span>0.158 mole + 0.09 mol + 0.044 mol) = 4.76 atm</span>
Answer:
Option C (a higher; the same) is the appropriate response.
Explanation:
Given:
Temperature,
T = 300 K (both 
and 
)
As we know,
Average speed of a molecule,
⇒ 
Thus, the average speed of will be lower as its molar mass is greater than .
Now,
⇒ 
(not depend on molar mass)
Hence, it will be the same.
The other three alternatives aren't connected to the scenario given. So the above is the correct answer.
Answer:
2CH3OH + 3O2 --> 2CO2 + 4H2O
This is called Combustion of Methanol
Explanation:
Count the numbers of atoms on each sides and try to get the same amount of quantity on each sides, so you'll eventually get "balanced".
or
Watch this video: "How to Balance CH3OH + O2 = CO2+ H2O (Combustion of Methanol)"
Good luck with future work! Keep studying chemistry!
- D
