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3 years ago

Balance CH3CHO + O2 → CO2 + H2O

Chemistry

1 answer:

babunello [35]3 years ago

7 0

2 CH3CHO + 5 O2 = 4 CO2 + 4 H2O

reaction type = combustion

hope this helped :)

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A mixture of so2(g) and o2(g), formed by the complete decomposition of so3(g), is collected over water at 34°c at a total pressu

Sedbober [7]

The decomposition of so3 to so2 gas and o2 gas can be described in the balanced chemical equation:

2so3(g) = 2 so2 (g) + 02(g).

so assuming a complete reaction, the ratio of so2 gas to total products is 2/3 while that of 02 is 1/3.

Subtracting water's water vapor pressure, 760-40 mm hG = 720 mm Hg.

then the products partial pressures are

so2 = 2/3 * (720) = 480 mm Hg.
o2 = 720-480 = 240 mm Hg.

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3 years ago

Which probe should be used to check the temperature of a chicken breast?

Eddi Din [679]

Answer:

penetration probe

Explanation:

it is a penetration probe

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2 years ago

Oxygen and hydrogen are both elements that are found as gases at room temperature. When oxygen combines with hydrogen, they prod

Tom [10]

Answer:

Explanation:

has properties that are different from the original substances.

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3 years ago

Do this Q7 if someone do I will her or him brainliest

Simora [160]

The average speed :

1. 10.44 m/s

2. 10.42 m/s

3. 9.26 m/s

The distance 100 m have the greatest average speed

<h3>Further explanation </h3>

Given

Distance and time of runner

Required

Average speed

Solution

<em> Average speed : total distance : total time </em>

1. d = 100 m, t = 9.58 s

Average speed : 100 : 9.58 = 10.44 m/s

2. d=200 m, t=19.19 s

Average speed : 200 : 19.19 = 10.42 m/s

3. d=400 m, t = 43.18 s

Average speed : 400 : 43.18 = 9.26 m/s

The distance 100 m have the greatest average speed

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2 years ago

How many moles of water would form the reaction of exactly 58.3 grams of magnesium hydroxide

Marat540 [252]

Answer:

$\boxed{\text{2.00 mol}}$

Explanation:

We know we will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

You don't tell us what the reaction is, but we can solve the problem so long as we balance the OH.

M_r: 58.32

Mg(OH)₂ + … ⟶ … + 2HOH

m/g: 58.3

(a) Moles of Mg(OH)₂

$\text{Moles of Mg(OH)$_{2}$} =\text{58.3 g Mg(OH)$_{2}$} \times \dfrac{\text{1 mol Mg(OH)$_{2}$}}{\text{58.32 g Mg(OH)$_{2}$}}\\\\=\text{0.9997 mol Mg(OH)$_{2}$}$

(b) Moles of H₂O

The molar ratio is 2 mol H₂O = 1 mol Mg(OH)₂.

$\text{Moles of H$_{2}$O}= \text{0.9995 mol Mg(OH)$_{2}$} \times \dfrac{\text{2 mol {H$_{2}$O}}}{ \text{1 mol Mg(OH)$_{2}$}}\\\\= \textbf{2.00 mol H$_{2}$O}$

The reaction will form $\boxed{\textbf{2.00 mol}}$ of water.

6 0

3 years ago