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Inessa05 [86]
3 years ago
15

Balance CH3CHO + O2 → CO2 + H2O

Chemistry
1 answer:
babunello [35]3 years ago
7 0
2 CH3CHO + 5 O2 = 4 CO2 + 4 H2O

reaction type = combustion

hope this helped :)

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a closed flask of air (0.250 L) contains 5.00 "puffs" of particles. The pressure probe on the flask reads 93 kPa. A student uses
Sergio039 [100]

Answer: New pressure inside the flask would be 148.8 kPa.

Explanation: The combined gas law equation is given by:

PV=nRT

As the flask is a closed flask, so the volume remains constant. Temperature is constant also.

So, the relation between pressure and number of moles becomes

P=n\\or\\\frac{P}{n}=constant

\frac{P_1}{n_1}=\frac{P_2}{n_2}

  • Initial conditions:

P_1=93kPa\\n_1=5\text{ puffs}

  • Final conditions: When additional 3 puffs of air is added

P_2=?kPa\\n_2=8\text{ puffs}

Putting the values, in above equation, we get

\frac{93}{5}=\frac{P_2}{8}\\P_2=148.8kPa

3 0
3 years ago
Complete and balance the molecular equation for the reaction of aqueous sodium carbonate, Na 2 CO 3 Na2CO3 , and aqueous nickel(
antoniya [11.8K]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of sodium carbonate and nickel (II) chloride is given as:

Na_2CO_3(aq.)+NiCl_2(aq.)\rightarrow 2NaCl(aq.)+NiCO_3(s)

Ionic form of the above equation follows:

2Na^{+}(aq.)+CO_3^{2-}(aq.)+Ni^{2+}(aq.)+2Cl^{-}(aq.)\rightarrow NiCO_3(s)+2Na^+(aq.)+2Cl^-(aq.)

As, sodium and chloride ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

Ni^{2+}(aq.)+CO_3^{2-}(aq.)\rightarrow NiCO_3(s)

Hence, the net ionic equation is written above.

3 0
4 years ago
If a frog initially contained 2 grams of carbon-14 and the half-life of carbon-14 is 5,730 years, how much carbon-14 remains in
andreyandreev [35.5K]
Half life is the time taken for a radioactive isotope to decay by half its original mass. In this case the half life of carbon-14 is 5.730 years. 
Using the formula;
New mass = original mass × (1/2)^n; where n is the number of half lives (in this case n=1 ) 
New mass = 2 g × (1/2)^1     
                  = 1 g
Therefore; the mass of carbon-14 that remains will be 1 g 
5 0
3 years ago
Identify the substance that conducts electricity. question 19 options: 1) nacl dissolved in water 2) solid nacl 3) solid sugar 4
Delicious77 [7]

The substance that conducts electricity is NaCl dissolved in water.

So, option A is correct one.

When the sodium chloride dissolve in water , the sodium atoms and chlorine atoms separates under the presence of water molecules and exist as sodium cation and chloride anion . Now , they are free to move around in the water as positively and negatively charged ions . This separation of charge allows the solution to conduct electricity.

The solid NaCl and solid sugar does not conduct electricity because it is not dissolve in water . Similarly, sugar dissolved in water does not conduct electricity .

to learn more about conduct electricity.

brainly.com/question/1458220

#SPJ4

4 0
2 years ago
The _____ method of pest control combines chemical and non-chemical methods and emphasizes the use of natural toxins.
labwork [276]
The answer to the question stated above is:
Integrated Pest Management is a method of agricultural pest control that combines chemical and non <span>chemical methods and emphasizes the use of natural toxins and effective pesticide.

>>N</span><span>atural toxins in plants can also be isolated and applied to crops like synthetic pesticides.</span>
4 0
3 years ago
Read 2 more answers
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