Answer:
 A) Sample B has more calcium carbonate molecules
Explanation:
M = Molar mass of calcium carbonate = 100.0869 g/mol
 = Avogadro's number = 
For the 4.12 g sample
Moles of a substance is given by

Number of molecules is given by

For the 19.37 g sample

Number of molecules is given by


So, sample B has more calcium carbonate molecules.
The ratio of the elements of carbon, oxygen, calcium atoms, ions, has to be same in both the samples otherwise the samples cannot be considered as calcium carbonate. Same is applicable for impurities. If there are impurites then the sample cannot be considered as calcium carbonate.
 
        
             
        
        
        
Answer:
357.475
Explanation:
First you need periodic table and you have to look for mass 
Fe = 3 x 55.845 = 167.535
P = 2  x 30.97 = 61.94
o = 4 x 2 so 8 oxygen =  8 x 16 = 128
 add all and you get 357.475
 
        
             
        
        
        
A mineral occurs naturally, meaning that even though there are artificial substances that might be described as mineral-like they are not minerals
        
             
        
        
        
<h2>
Answer:</h2>
<h3>Hg2 ( NO2 )2</h3>
<h2>Explanation:</h2>
<h3>Formula of mercury ( 1 ) dioxonitrate 111 is Hg2 ( NO2 )2//</h3>
 
        
             
        
        
        
Answer : The molecular weight of this compound is 891.10 g/mol
Explanation :  Given,
Mass of compound = 12.70 g
Mass of ethanol = 216.5 g
Formula used :  

where,
 = change in freezing point
 = temperature of pure ethanol = 
 = temperature of solution = 
 = freezing point constant of ethanol = 
i = van't hoff factor = 1   (for non-electrolyte)
m = molality
Now put all the given values in this formula, we get


Therefore, the molecular weight of this compound is 891.10 g/mol