The mathematical and proportional relationship between mL and 
said us that 
is equivalent to 1mL.
If the density is considered as the amount of mass per unit volume we will have to
here,
m = mass
V = Volume
Replacing we have that
As 
we have that the density in g/mL is,
Answer:A uniform ladder of mass and length leans at an angle against a frictionless wall .If the coefficient of static friction between the ladder and the ground is , determine a formula for the minimum angle at which the ladder will not slip.
Explanation:A uniform ladder of mass and length leans at an angle against a frictionless wall .If the coefficient of static friction between the ladder and the ground is , determine a formula for the minimum angle at which the ladder will not slip.
<span>122.0 km/hr. First let’s make sure all of our units are in the base meter form: i.e. convert 5km to 5000m. (We will convert back to km later). The first thing to do is look at the equation relating velocity, acceleration, and distance: Vf^2 = Vi^2 + 2*a*d, where Vf is final velocity, Vi is initial velocity, a is acceleration, and d is distance. 25^2 = 10^2 + 2*a*5000 =?> 625 = 100 +10000a => a= 0.0525m/s^2. Now that we have acceleration, we can use the same equation again with different numbers.: Vf^2 = Vi^2 + 2*a*d = 25^2 + 2*0. 0525m*5000 = 625 + 525 =1150 => Vf^2 = 1150 => 33.9m/s. Convert to km/hour: 33.9m/s * 1km/1000m *60s/1min * 60min/ 1 hr = 122.0 km/hr.</span>
Short Answer- Friction
Explanation- There is friction between the grass and the ball. Friction is a type of force that limits motion between two surfaces that are touching. Friction is the force that one surface exerts on another with the two surfaces rubbing together.
This is the answer, hope it helps :)
At the start, the ball is at rest and therefore, u=0 m/s. As it leaves the bat, v= 50 m/s
From equations of motion, v=u+at = at (since u=o)
a=v/t = 50/0.04 = 121250 m/s^2
From Newton's second law,
F=ma = 145/1000 *1250 = 181.25 N
