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hichkok12 [17]
4 years ago
14

What is the maximum speed with which a 1200-kg car can round a turn of radius 90.0 m on a flat road if the coefficient of static

friction between tires and road is 0.70?
2. Is this result independent of the mass of the car?
Physics
2 answers:
KATRIN_1 [288]4 years ago
6 0

Answer:

78.6m/s

Explanation:

We know that frictional force also contributes to the centripetal force that keeps the car in circular motion in the turn

And is given as

F= mv²/r

But the frictional force is

F= ugm

= = 0.7*1200*9.8= 8232N

To find maximum velocity v we say

V= √F x r/m

= √ 8232* 90 /1200

= 78.6m/s

2. Yes it is independent of mass of car

Readme [11.4K]4 years ago
6 0

Answer:

The value is v =  24.85 \ m/s

Yes

Explanation:

From the question we are told that

  The mass of the car is  m= 1200 \  kg

    The  radius  is r =  90 \ m

    The coefficient of static friction is  \mu_s  =  0.70

Generally at maximum speed the centripetal force acting on the car is equal to the friction force on the car

So

    F_c  =  F_f

        \frac{m v^2}{r}  =  \mu_s  * m * g

=>   v  =  \sqrt{\mu_s  *  g  * r }

=>   v  =  \sqrt{ 0.70  *  9.8   * 90 }

=>    v =  24.85 \ m/s

Yes the value is independent of the mass because from the equation above we see that v is independent of mass

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Answer:

s =  1.7 m

Explanation:

from the question we are given the following:

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velocity of package (v) = 170 m/s

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Assuming that no non conservative force is acting on the system here, the initial and final energies of the system will be the same. Therefore  

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• \frac{1}{2}ks^{2} + (-\frac{GMm}{r}) = \frac{1}{2}mv^{2}  

• s = \sqrt{\frac{m}[k}(v^{2}+\frac{2GM}{r})}

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3 years ago
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6 0
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One mole of titanium contains how many atoms?
Vladimir [108]

Answer:

\boxed {\boxed {\sf D. \ 6.02*10^{23} \ atoms}}

Explanation:

One mole of a substance contains the same amount of representative particles. These particles can be atoms, molecules, ions, or formula units. In this case, the particles are atoms of titanium.

Regardless of the particles, there will always be <u>6.02*10²³</u> (also known as Avogadro's Number) particles in one mole of a substance.

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3 years ago
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3 years ago
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A square plate of edge length 9.0 cm and negligible thickness has a total charge of 6.90 10-6 C. Estimate the magnitude E of the
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Answer:

E= 4.35*10^6 N/C

Explanation:

Let's find the area charge density of the plate

α= 6.9*10^-6/9*10^-2 = 7.7*10^-5C/m2

Now we can calculate the electric field just of the plate

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7 0
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