Answer:
Horizontal component of velocity = 241.61 m/s
Explanation:
Given that,
Velocity of a jetliner is 245 m/s
The vertical component of the plane's velocity is 40.6 m/s, 
We need to find the magnitude of the horizontal component of the plane velocity.
The resultant velocity is given by :
Where, 
is the horizontal component of the plane velocity
So, the magnitude of the horizontal component of the plane velocity is 241.61 m/s.
Vfinal = Vinitial + at
Vinitial = 0
a = 9.8 m/s^2
t = 8s
Vfinal = 0 + 9.8 * 8
ANSWER: 78.4 m/s
Answer:
K.E = 5.53 eV = 8.85 x 10⁻¹⁹ J
Explanation:
First we calculate the energy of photon:
E = hc/λ
where,
E = Energy of Photon = ?
h = Plank's Constant = 6.626 x 10⁻³⁴ J.s
c = speed of light = 3 x 10⁸ m/s
λ = wavelength = 120 nm = 1.2 x 10⁻⁷ m
Therefore,
E = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(1.2 x 10⁻⁷ m)
E = (16.565 x 10⁻¹⁹ J)(1 eV/1.6 x 10⁻¹⁹ J)
E = 10.35 eV
Now, from Einstein's Photoelectric equation we know that:
Energy of Photon = Work Function + K.E of Electron
10.35 eV = 4.82 eV + K.E
K.E = 10.35 eV - 4.82 eV
<u>K.E = 5.53 eV = 8.85 x 10⁻¹⁹ J</u>
