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hram777 [196]
3 years ago
14

Which of the following are responsible for surface currents a. the wind and density

Chemistry
2 answers:
SCORPION-xisa [38]3 years ago
7 0
B-wind and the earth's rotation
GREYUIT [131]3 years ago
4 0

Answer: b. wind and the earth rotation

Explanation:

The surface oceanic water currents originates in the water due to the wind currents blowing over the surface of the water creating a specific pattern in the water and the other factor responsible is spinning motion of the earth. The surface oceanic currents forms a large circular pattern in the water that is called as gyre.

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In order for a process to be spontaneous, Multiple Choice the entropy of the surroundings must increase. the entropy of the surr
Crazy boy [7]

Answer:

The correct answer is entropy change of the surrounding plus the entropy change of the system must be positive.

Explanation:

The term entropy is a state function.Entropy can be defined as the disorder or randomness of the molecules in a system.

 A spontaneous reaction is a type of reaction which deals with the release of free energy.The change of free energy in case of spontaneous reaction is always negative.

 According to the second law of thermodynamics a spontaneous reaction will occur in a system if the total entropy of both  system and surrounding increases during the reaction.

8 0
3 years ago
11. The back part of the cerebrum deals with hearing<br><br> True<br><br> False
Sunny_sXe [5.5K]

Answer:

The answer is: True

5 0
3 years ago
The initial pressure and volume of a gas are 55.16 kilopascals and 0.500 liter. According to Boyle’s law, if the volume of the g
Gnesinka [82]

Answer: The final pressure is 34.48kPa

Initial Pressure P1 = 55.16kPa

Initial Volume V1 = 0.500L

Final Pressure P2 = ?

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Boyle's law P1V1 = P2 V2

P2 = P1V1/V2

P2 = 55.16*0.5/0.8

P2 = 34.48kPa

7 0
3 years ago
The particle size of solute particles does not affects the rate. Question 14 options: True False
stepan [7]
The answer is false
8 0
4 years ago
How much heat energy is required to raise the temperature of 0.360 kg of copper from 23.0 ∘C to 60.0 ∘C? The specific heat of co
AVprozaik [17]
MThe  heat  energy  required  to  raise  the  temperature   of  0.36Kg   of  copper   from   22 c   to  60  c  is  calculate  using  the  following  formula

MC delta T
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heat  energy is therefore=  360g   x0.0920 cal/g.c  x 37  c=  1225.44  cal

5 0
3 years ago
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