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hram777 [196]
3 years ago
14

Which of the following are responsible for surface currents a. the wind and density

Chemistry
2 answers:
SCORPION-xisa [38]3 years ago
7 0
B-wind and the earth's rotation
GREYUIT [131]3 years ago
4 0

Answer: b. wind and the earth rotation

Explanation:

The surface oceanic water currents originates in the water due to the wind currents blowing over the surface of the water creating a specific pattern in the water and the other factor responsible is spinning motion of the earth. The surface oceanic currents forms a large circular pattern in the water that is called as gyre.

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Is NaCl an ionic or covalent compound?<br>Explain.​
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NaCl is an ionic compound because Chlorine is a nonmetal and Sodium is a metal (Alkali Metal Group)
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Physical science:verification on newton's second law
mezya [45]

Explanation:

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2 years ago
A lead mass is heated and placed in a foam cup calorimeter containing 40.0 mL of water at 17.0°C. The water reaches a temperatur
lbvjy [14]

Answer: 502 Joules

Explanation:

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 40.0 mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{40.0mL}\\\\\text{Mass of water}=(1g/mL\times 40.0mL)=40.0g

When metal is dipped in water, the amount of heat released by lead will be equal to the amount of heat absorbed by water.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

q=m\times c\times \Delta T

q = heat absorbed by water

m = mass of water = 40.0 g

T_{final} = final temperature of water = 20.0°C

T_{initial = initial temperature of water = 17.0°C

c = specific heat of water= 4.186 J/g°C

Putting values in equation 1, we get:

q=40.0\times 4.186\times (20.0-17.0)]

q=502J

Hence, the joules of heat were re-leased by the lead is 502

5 0
3 years ago
How many neutrons are in selenium -36?
Soloha48 [4]

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5 0
3 years ago
Given the balanced equation, 2 H2 + O2 -&gt; 2 H2O, answer the following
9966 [12]

Answer: O_2 is the limiting reagent

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} H_2=\frac{10.0g}{2g/mol}=5.00moles

\text{Moles of} O_2=\frac{20.0g}{32g/mol}=0.625moles

The balanced chemical reaction is :

2H_2+O_2\rightarrow 2H_2O

According to stoichiometry :

1 moles of O_2 require = 2 moles of H_2

Thus 0.625 moles of O_2 will require=\frac{2}{1}\times 0.625=1.25moles of H_2

Thus O_2 is the limiting reagent as it limits the formation of product and H_2 is the excess reagent as it is present more than the required amount.

8 0
3 years ago
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