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Scorpion4ik [409]
2 years ago
15

A chemist determines by measurements that 0.0200 moles of iodine solid participate in a chemical reaction. Calculate the mass of

iodine solid that participates. Round your answer to 3 significant digits. $ x 6 ?
Chemistry
1 answer:
tiny-mole [99]2 years ago
5 0

Answer:

The answer is 5.076 g of iodine solid.

Explanation:

The molecular formula of <u>iodine</u> is I₂.

Molecular weight of I₂= molecular mass of I x 2 = 126.904 /mol x 2= 253.808 g/mol

Thus, to calculate the mass of I₂ there is in a mol, we have to multiply the amount of mol of I₂ by its molecular weight as follows:

0.0200 mol I₂ x 253.808 g/mol I₂ = 5.07616 g

The mass rounded to 3 significant digits is 5.076 g

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The standard emf for the cell using the overall cell reaction below is +2.20 V:
ANEK [815]

Answer:

emf generated by cell is 2.32 V

Explanation:

Oxidation: 2Al-6e^{-}\rightarrow 2Al^{3+}

Reduction: 3I_{2}+6e^{-}\rightarrow 6I^{-}

---------------------------------------------------------------------------------

Overall: 2Al+3I_{2}\rightarrow 2Al^{3+}+6I^{-}

Nernst equation for this cell reaction at 25^{0}\textrm{C}-

E_{cell}=E_{cell}^{0}-\frac{0.059}{n}log{[Al^{3+}]^{2}[I^{-}]^{6}}

where n is number of electrons exchanged during cell reaction, E_{cell}^{0} is standard cell emf , E_{cell} is cell emf , [Al^{3+}] is concentration of Al^{3+} and [Cl^{-}] is concentration of Cl^{-}

Plug in all the given values in the above equation -

E_{cell}=2.20-\frac{0.059}{6}log[(4.5\times 10^{-3})^{2}\times (0.15)^{6}]V

So, E_{cell}=2.32V

3 0
2 years ago
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Flura [38]

Answer:

Combining the two clear colorless liquids is a chemical change.

Explanation:

Because a different solid substance is formed. Tell students that a precipitate is an insoluble solid that forms when two solutions are combined and react chemically. Insoluble means that the solid will not dissolve.

3 0
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Answer:

Explanation:

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What is true about ionic compounds?
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