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Scorpion4ik [409]
3 years ago
15

A chemist determines by measurements that 0.0200 moles of iodine solid participate in a chemical reaction. Calculate the mass of

iodine solid that participates. Round your answer to 3 significant digits. $ x 6 ?
Chemistry
1 answer:
tiny-mole [99]3 years ago
5 0

Answer:

The answer is 5.076 g of iodine solid.

Explanation:

The molecular formula of <u>iodine</u> is I₂.

Molecular weight of I₂= molecular mass of I x 2 = 126.904 /mol x 2= 253.808 g/mol

Thus, to calculate the mass of I₂ there is in a mol, we have to multiply the amount of mol of I₂ by its molecular weight as follows:

0.0200 mol I₂ x 253.808 g/mol I₂ = 5.07616 g

The mass rounded to 3 significant digits is 5.076 g

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A solution contains 0.115 mol h2o and an unknown number of moles of nacl. the vapor pressure of the solution at 30°c is 25.7 tor
Valentin [98]
According to Raoult's low:
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∴ mole fraction of solvent = Vp(Solu) / Vp (Solv)
when we have Vp(solu) = 25.7 torr & Vp(solv) = 31.8 torr 
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when we assume the moles of solute NaCl = X 
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