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Scorpion4ik [409]
3 years ago
15

A chemist determines by measurements that 0.0200 moles of iodine solid participate in a chemical reaction. Calculate the mass of

iodine solid that participates. Round your answer to 3 significant digits. $ x 6 ?
Chemistry
1 answer:
tiny-mole [99]3 years ago
5 0

Answer:

The answer is 5.076 g of iodine solid.

Explanation:

The molecular formula of <u>iodine</u> is I₂.

Molecular weight of I₂= molecular mass of I x 2 = 126.904 /mol x 2= 253.808 g/mol

Thus, to calculate the mass of I₂ there is in a mol, we have to multiply the amount of mol of I₂ by its molecular weight as follows:

0.0200 mol I₂ x 253.808 g/mol I₂ = 5.07616 g

The mass rounded to 3 significant digits is 5.076 g

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I believe the correct response would be A. More neutrons than protons.
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3 years ago
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Complete and balance each of the following equations for gas evolution reactions HCl(aq)+ZnS(s)&gt;
DENIUS [597]

2HCl(aq) + ZnS(s) ⇒ ZnCl₂(aq) + H₂S(g)

<h3>Further explanation  </h3>

Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:  

  • 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.  
  • 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product  
  • 3. Select the coefficient of the substance with the most complex chemical formula equal to 1  

Reaction

HCl(aq) + ZnS(s) ⇒ ZnCl₂(aq) + H₂S(g)

1. give equation

aHCl(aq) + bZnS(s) ⇒ ZnCl₂(aq) + cH₂S(g)

2. make an equation

H, left=a, right=2c⇒a=2c(eq 1)

Cl, left=a, right=2⇒a=2⇒c=1(from eq 1)

Zn, left=b, right=1⇒b=1

So the equation :

2HCl(aq) + ZnS(s) ⇒ ZnCl₂(aq) + H₂S(g)

4 0
3 years ago
How many milliliters of 0.500 M NaOH should be added to 10.0 g of tris hydrochloride (FM 121.135) to give a pH of 7.60 in a fina
liubo4ka [24]

Answer:

41.64mL of NaOH 0.500M must be added to obtain the desire pH

Explanation:

It is possible to find pH of a buffer by using H-H equation, thus:

pH = pka + log [A⁻] / [HA]

<em>Where [HA] is concentration of the weak acid TRIS-HCl and [A⁻] is concentration of its conjugate acid.</em>

Replacing in H-H equation:

7.60 = 8.072 + log [A⁻] / [HA]

0.3373 =  [A⁻] / [HA] <em>(1)</em>

10.0g of TRIS-HCl (Molar mass: 121.135g/mol) are:

10.0g ₓ (1mol / 121.135g) = 0.08255 moles of acid. That means moles of both the acid and conjugate base are:

[A⁻] + [HA] = 0.08255 <em>(2)</em>

Replacing (1) in (2):

0.3373 =  0.08255 - [HA] / [HA]

0.3373[HA] =  0.08255 - [HA]

1.3373[HA] = 0.08255

<em>[HA] = 0.06173 moles</em>

Thus:

[A⁻]  = 0.08255 - 0.06173 = 0.02082 moles [A⁻]

The moles of A⁻ comes from the reaction of the weak acid with NaOH, that is:

HA + NaOH → A⁻ + H₂O + K⁺

Thus, <em>you need to add 0.02082 moles of NaOH to produce 0.02082 moles of A⁻. </em>As NaOH solution is 0.500M:

0.02082 moles NaOH ₓ (1L / 0.500mol) = 0.04164L of NaOH 0.500M =

<h3>41.64mL of NaOH 0.500M must be added to obtain the desire pH</h3>

3 0
3 years ago
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Answer:

I thinks it's stress caused by plate movement hope this helps

4 0
3 years ago
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Sonja and Jeremy performed several experiments to show how changes in temperature affected the volume of an inflated balloon. Th
ycow [4]

Answer:

They also showed the effects of pressure on volume if temperature stayed the same

Explanation:

They also showed the effects of pressure on volume if temperature stayed the same is the experiment that will provide an evidence for Boyle's law.

Boyle's law states that "the volume of a fixed mass of a gas varies inversely as the pressure changes, if the temperature is constant".

  • The law is an affirmation of what happens when there is a dynamics between pressure and volume if temperature is made constant.
  • So the experiment designed to investigate this proves and shows Boyle's law.
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3 years ago
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