Answer:
Explanation:
In order to a molecule or ion have <em>resonance </em>structures (named resonance contributors) it must have a π bond.
π bonds are in double or triple bonds. Single bonds are formed by sigma bonds.
Resonance structures are alternate representations for the same molecule or ion with different structures. Every structure will have the same number of electrons, but the electrons can move from one atom to another, which can only be done between π bonds; never between sigma bonds.
In the ion [NH₄]⁺ there are only sigma bonds: the N atom is at the centre of the iona, bonded to four H atoms; each N - H bond is a sigma bond. So, this structure does not exhibit any resonance.
On the other hand, [NO₃] ⁻ has a double bond between one of the oxygen atoms and the N atom at the centre. So, ion has a π bond, which indicates that there are resonance structures.
Answer:
Fe
Explanation:
The electrical conductivity depends mainly on the type of chemical bonds between the atoms of a compound.
In the case of MgF2, FeCl3 and FeO3, these have the type of ionic bond. This means that in the atoms of the compound there is an electron transfer, to keep eight electrons in the outermost layer and thus resemble the electronic configuration of the inert gas closest to each of the two elements, due to this ions of opposite charges are formed that are held together by electrostatic forces. These types of compounds are good conductors of electricity, however, to have this property, they must be dissolved in water or molten.
In the case of Fe, however, the type of union between atoms is metallic. In this type of junction, valence electrons are quite free inside the metal, which makes it easy for them to move. For this reason, this compound will conduct electricity in a solid state.
Answer: You probably know it now So um have great day
Explanation:
All of the noble gasses have a complete valence electron shell so the only applicable answer for your question is argon :)
Hope this helps!!
:)
V = f 入 (velocity = frequency x wavelength)
<span>If we have the speed ( for wave in vacuum </span><span>i.e. 3 x 10^8 m/s) </span>
<span>Then the frequency of x-ray is </span>
<span>(3 x 10^8) ÷(1.15 x 10^-10) = 2.61 x 10^18 </span>