Answer:
SiH4
Explanation:
We must remember that the magnitude of intermolecular forces play a vital role in the determination of the boiling point of a substance.
The Si-H bond is the least polar among all the bonds in compounds listed in the question. This is because the electronegativity difference between silicon and hydrogen is very slim resulting in the formation of a nonpolar covalent bond.
The other compounds possess more polar bonds hence have a greater degree of dipole interaction between molecules and a consequently higher boiling point than SiH4.
Answer is 355 grams.
Explanation:
Given the molecular weights:
M
r
N
a
O
H
=
40
g
m
o
l
M
r
N
a
2
S
O
4
=
142
g
m
o
l
The analogy of the moles will be held constant:
n
N
a
O
H
n
N
a
2
S
O
4
=
2
1
n
N
a
O
H
n
N
a
2
S
O
4
=
2
For each one, substitute:
n
=
m
M
r
Therefore:
n
N
a
O
H
n
N
a
2
S
O
4
=
2
m
N
a
O
H
M
r
N
a
O
H
m
N
a
2
S
O
4
M
r
N
a
2
S
O
4
=
2
200
40
x
142
=
2
200
⋅
142
40
x
=
2
200
⋅
142
=
2
⋅
40
x
x
=
200
⋅
142
2
⋅
40
=
100
⋅
142
40
=
10
⋅
142
4
=
1420
4
=
=
710
2
=
355
g
r
a
m
s
(or just use a calculator)
I believe it is low frequency.
Answer:
10
Explanation:
ur pefrct no matter the inside or outside
Answer:
138.6 g of C₂HF₃O₂ have 38.9 g of O
Explanation:
Trifluoroacetic acid → C₂HF₃O₂
Molar mass = Mass of C . 2 + Mass of H + Mass of F . 3 + Mass of O .2
Molar mass = 12 . 2 + 1 . 1 + 19 . 3 + 16 . 2 = 114 g /mol
1 mol of C₂HF₃O₂ has:
2 moles of C
1 mol of H
3 moles of F
2 moles of O
If we state the relation in mass by g we say:
114 g of C₂HF₃O₂ have 24g of C, 1 g of H, 57 g of F and 32 g of O
Let's make a rule of three:
32 g of O are contained in 114 g of C₂HF₃O₂
38.9 g of O may be contained in (38.9 . 114) / 32 = 138.6 g
