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Airida [17]
2 years ago
13

Onsider the following elementary reaction:

Chemistry
1 answer:
Brilliant_brown [7]2 years ago
3 0

Answer:

C_{O_2}=\frac{k_2C_{NO_2}C_{O}}{k_1C_{NO}}

Explanation:

Hello,

In this case, for the given elementary reaction, the rate law takes the form:

r=-k_1C_{NO}C_{O_2}+k_2C_{NO_2}C_{O}

Nevertheless, at equilibrium, the rate becomes zero:

0=-k_1C_{NO}C_{O_2}+k_2C_{NO_2}C_{O}

Thus, we can solve for the concentration of O₂ in terms of the rate constants as shown below:

k_1C_{NO}C_{O_2}=k_2C_{NO_2}C_{O}\\\\C_{O_2}=\frac{k_2C_{NO_2}C_{O}}{k_1C_{NO}}

Best regards.

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DedPeter [7]

Answer:

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3 0
3 years ago
On the basis of the Ksp values below, what is the order of the solubility from least soluble to most soluble for these compounds
Viktor [21]

Answer:

The order of solubility is AgBr <   Ag₂CO₃ < AgCl

Explanation:

The solubility constant give us the molar solubilty of ionic compounds. In general for a compound AB the ksp will be given by:

Ksp = (A) (B) where A and B are the molar solubilities = s²  (for compounds with 1:1  ratio).

It follows then  that the higher the value of Ksp the greater solubilty of the compound if we are comparing compounds with the same ionic ratios:

Comparing AgBr: Ksp = 5.4 x 10⁻¹³ with AgCl: Ksp = 1.8 x 10⁻¹⁰, AgCl will be more soluble.

Comparing Ag2CO3: Ksp = 8.0 x 10⁻¹²  with AgCl Ksp = AgCl: Ksp = 1.8 x 10⁻¹⁰ we have the complication of  the ratio of ions 2:1 in Ag2CO3,  so the answer is not obvious. But since we know that

Ag2CO3 ⇄ 2 Ag⁺ + CO₃²₋

Ksp Ag2CO3  = 2s x s = 2 s² =  8.0 x 10-12

s = 4 x 10⁻12 ∴ s= 2 x 10⁻⁶

And for AgCl

AgCl  ⇄ Ag⁺ + Cl⁻

Ksp = s² = 1.8 x 10⁻¹⁰  ∴ s = √ 1.8 x 10⁻¹⁰   = 1.3 x 10⁻⁵

Therefore, AgCl is more soluble than Ag₂CO₃

The order of solubility is AgBr <   Ag₂CO₃ < AgCl

8 0
3 years ago
Read 2 more answers
The reaction is first order in cyclopropane and has a measured rate constant of k=3.36×10−5 s−1 at 720 k. if the initial cyclopr
sergey [27]

Answer:

0.0277 M.

Explanation:

The integral rate law of a first order reaction:

<em>Kt = ln ([A₀]/[A]),</em>

where, k is the rate constant of the reaction <em>(k = 3.36 × 10⁻⁵ s⁻¹)</em>,

t is the time of the reaction <em>(t = 235.0 min = 14100 s)</em>,

[A₀] is the initial concentration of cyclopropane <em>([A₀] = 0.0445 M)</em>

<em>∵ Kt = ln ([A₀]/[A]),</em>

∴ (3.36 × 10⁻⁵ s⁻¹)(14100 s) = ln (0.0445 M)/[A]

Taking the exponential of both sides:

1.6 = (0.0445 M)/[A]

<em>∴ [A] = (0.0445 M)/1.6 = 0.0277 M.</em>

<em />

6 0
3 years ago
SOMEONE PLS HELP ME ITS URGENT
Simora [160]

If copper is heated with iron oxide there is no obvious reaction because

copper is less reactive than iron.

On a reactivity chart, copper is far below iron. This makes it impossible for a replacement reaction to occur, so the equation doesn't change.

I hope I helped!

5 0
3 years ago
Read 2 more answers
Is this equation completely balanced? 2C8H8 + 25O2 8CO2 + 18H2O No, because the number of carbon, hydrogen &amp; oxygen atoms on
Sergio039 [100]
<span>So to make it clear let's break the equation down species by species and assess the number of each species on bothe sides of the equation:
                   2C</span>₈H₈  +  25O₂   →   8CO₂ +  18H₂<span>O
LHS:  C - 16                                           RHS:  C - 8
          H - 16                                                     H - 36
          O - 50                                                    O - 34

Thus based on that it is evident that the equation is not quite balanced.  This therefore means a "</span><span>No, because the number of carbon, hydrogen & oxygen atoms on both sides of the equation are not equal."

</span>The actual balance equation would be C₈H₈  +  10O₂   →   8CO₂ +  4H₂O
8 0
3 years ago
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