Question

Onsider the following elementary reaction:

Answer 1

Answer:

$C_{O_2}=\frac{k_2C_{NO_2}C_{O}}{k_1C_{NO}}$

Explanation:

Hello,

In this case, for the given elementary reaction, the rate law takes the form:

$r=-k_1C_{NO}C_{O_2}+k_2C_{NO_2}C_{O}$

Nevertheless, at equilibrium, the rate becomes zero:

$0=-k_1C_{NO}C_{O_2}+k_2C_{NO_2}C_{O}$

Thus, we can solve for the concentration of O₂ in terms of the rate constants as shown below:

$k_1C_{NO}C_{O_2}=k_2C_{NO_2}C_{O}\\\\C_{O_2}=\frac{k_2C_{NO_2}C_{O}}{k_1C_{NO}}$

Best regards.