Answer: The horizontal location of the plane will BE OVER THE BOMB
Explanation:
As soon as the bomb was dropped, the bomb will fall under gravity (free fall) and the location of the plane continues to increase horizontally till the bomb reaches the ground which is a falling distance to be travelled by the bomb at 9.8m/s²
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Answer:
Explanation:
The angular momentum of electron mvR = 6 x 10⁻²⁵ Js
Magnetic field B = 2.5 x 10⁻³ T
radius of circular path R = mv / Bq
where m is mass , v is velocity and q is charge on electron
R² = mvR / Bq
R² = 6 x 10⁻²⁵ / 2.5 x 10⁻³ x 1.6 x 10⁻¹⁹
= 1.5 x 10⁻³
R = 3.87 x 10⁻² m
mvR = 6 x 10⁻²⁵
v = 6 x 10⁻²⁵ / mR
= 6 x 10⁻²⁵ / 9.1 x 10⁻³¹ x 3.87 x 10⁻²
= .17 x 10⁸
= 17 x 10⁶ m/s
