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Alex17521 [72]
3 years ago
9

12. Aditya is stacking some cups. The diagram above shows the cups before they touch each other. Use the information in the diag

ram to answer the question.
After the cups have been touching for a while, which of the two bottom cups will be cooler, and why?
Chemistry
2 answers:
Pepsi [2]3 years ago
8 0
Aditya would be the cooler person in this situation I think idk
Kobotan [32]3 years ago
4 0

Answer:

please give more clarification

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Find the empirical and the molecular formula of acetylene gas composed of 92.26 percent carbon and 7.74 percent hydrogen
Hitman42 [59]

Answer:

CH

Explanation:

92.26% = 92.26 g

7.74% = 7.74 g

carbon is 92.26 x 1 mole/12.011 = 7.68

hydrogen is 7.74 x 1 mole/1.008 = 7.68

carbon 7.68 ÷ hydrogen 7.68 = 1

so 1 is your subscript for both carbon and hydrogen

6 0
3 years ago
The picture is above^ someone help me please :)
Ronch [10]

Answer:

idk plz do not report

Explanation:

8 0
3 years ago
Vanadium crystallizes in a body-centered cubic lattice, and the length of the edge of a unit cell is 305 pm. What is the density
Anestetic [448]

Answer:

5.96 g/cm^3

Explanation:

Corner atom = 1/8

Atoms in center = 1

Atoms in face of the cube= 1/2  

Molar mass of V = 50.94 g/mol <em>(from period table)</em>

1 mole = 6.02x10^23

<em>In BCC unit cell:</em>

(8 x 1/8)+ 1=2 per 1 unit cell

<em>Mass: </em>2(50.94g)/6.02x10^23 = 1.69x10^-22 g/unit cell

305pm=(305x10^-12m÷10^-2m) x (1mL÷1cm^3)

           = 2.837 x 10^-23 mL

<em>1pm=10^-12m</em>

<em>1cm=10^-2m</em>

<em>1mL=1cm^3</em>

<em></em>

density=mass/volume

density of V = 1.69x10^-22g÷2.837x10^-23mL

                    =5.957g/mL

                    =5.96g/cm^3

5 0
2 years ago
In terms of entropy and energy, systems in nature tend to undergo changes toward
andrew-mc [135]
Number 2 lower entropy and higher entropy
7 0
2 years ago
On a summer day, you take a road trip through Chelan, WA, in a Tesla Model S. You start out at a temperature of 19°C in the morn
ASHA 777 [7]

1. 1.636 moles

2. 271.06 kPa pressure

3. Tires will be burst

4. 235.91 kPa

Explanation:

Step 1:

PV = nRT, is the equation to be used where

P represents pressure

V represents volume

n represents moles of gas

R is constant

T represents temperature in Kelvin

n=RT/PV  

It is given that the pressure is 245 kPa at initial temperature 19 C and tire volume is 16.2 L. Temperature must be converted  to Kelvin, 19 C equals 292K.

n=PV/RT ->245*16.2/(8.31*292) = 1.636

Number of moles of Nitrogen in the tire = 1.636

Step 2:

We need to find the maximum tire pressure at 50 C (323K)

P = nRT/V

Substituting the values P = (1.636 * 8.31 * 323)/16.2 = 271.06 kPa

The tire pressure at 50 C will be 271.06 kPa

Step 3

We need to figure out if the tires would burst in Chelan when the temperature is 55 C. It is given that the maximum pressure the tires can withstand is 265 kPA, so any pressure above this will cause the tire to burst. In Step-2 we calculated that the pressure is 271.06 kPA at 50 C which is more than the maximum pressure the tire can withstand. The pressure would increase further with temperature and at 55 C the pressure will be more than 271.06 kPa. So the tires are likely to burst in Chelan.

Step 4:

We need to find the pressure of Nitrogen at 19 C before the start of the trip so that tires will not burst. The pressure at 55 C is 265 kPa. Let us find the number of moles at this temperature and pressure.

n= PV/RT -> n=265*16.2/(8.31*328) = 1.575

Now let us find the pressure at 19 C.

P = nRT/V -> 1.575*8.31*292/16.2 = 235.91 kPa

8 0
3 years ago
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