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tester [92]
3 years ago
14

Choose the chemical equation that is correctly balanced. 2Ca(s) + Cl2(g) → CaCl2(s) 4Mg(s) + O2(g) → 2MgO(s) Li(s) + Cl2(g) → 2L

iCl(s) C(s) + O2(g) → CO2(g)
Chemistry
2 answers:
boyakko [2]3 years ago
5 0

Answer:

C(s) + O2(g) → CO2(g)

Explanation:

I took the test.

Tju [1.3M]3 years ago
4 0

Answer:

Last option C(s) + O2(g) → CO2(g)

Explanation:

The reactions are:

2Ca(s) + Cl2(g) → CaCl2(s)

4Mg(s) + O2(g) → 2MgO(s)

Li(s) + Cl2(g) → 2LiCl(s)

C(s) + O2(g) → CO2(g)

Let's count the atoms (check out the stoichiometry):

1. We have 2 Ca in reactant side and 2Cl, in product side we have 1 Ca and 2 Cl. UNBALANCED

2. We have 4 Mg in reactant side and 2 O. In product side we have 2 Mg and 2 O. UNBALANCED

3. In reactant side we have 1 Li and 2 Cl. Then, in product side we have 2Li and 2Cl. UNBALANCED

C(s) + O2(g) → CO2(g)

1 C and 2 O ⇒ 1 C and 2 O         Correctly balanced

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lutik1710 [3]
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initial                0.15                     0      0
change             -X                     +X      +X
at equlibrium 0.15-X                  X        X
because Ka1 is small we can assume neglect x in H2X concentration
     Ka1      = [HX][H3O]/[H2X]
4.5x10^-6 =( X )(X) / (0.15)
X = √(4.5x10^-6*0.15) 
∴X = 8.2 x 10-4 m
∴[HX] & [H3O] = 8.2x10^-4
the second dissociation of H2X
        HX + H2O↔ X^2 + H3O
    8.2x10^-4          Y         8.2x10^-4
Ka2 for Hx = 1.2x10^-11
Ka2       = [X2][H3O]/[HX]
1.2x10^-11= y (8.2x10^-4)*(8.2x10^-4)
∴y = 1.78x10^-5
∴[X^2] = 1.78x10^-5 m


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