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2 years ago

If 0.400 moles CO and 0.400 moles O2 completely react how many grams of CO2 are produces?

Chemistry

1 answer:

True [87]2 years ago

7 0

If 0.400 moles CO and 0.400 moles O2 completely react, 17.604 grams of CO2 would be produced.

First, let us look at the balanced equation of reaction:

$2CO + O_2 ---> 2CO_2$

According to the equation, the mole ratio of CO and O2 is 2:1. But in reality, the mole ratio supplied is 1:1. Thus, CO is the limiting reactant while O2 is in excess.

Also from the equation, the ratio of CO consumed to that of CO2 produced is 1:1. Thus, 0.400 moles of CO2 would also be produced from 0.400 moles of CO.

Recall that: mole = mass/molar mass

Therefore, the mass in grams of CO2 that would be produced from 0.400 moles can be calculated as:

Mass = mole x molar mass

= 0.400 x 44.01

= 17.604 grams

More on calculating mass from number of moles can be found here: brainly.com/question/12513822

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Ammonium dihydrogen phosphate, formed from the reaction of phosphoric acid with ammonia, is used as a crop fertilizer as well as

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Answer:

a)The mass percentages of nitrogen and phosphorus in the compound is 24.34% and 26.95% respectively.

b) 14.78 grams ammonia is incorporated into 100. g of compound.

Explanation:

a) Ammonium dihydrogen phosphate that is $NH_6PO_4$ .

Molecular mass of ammonium dihydrogen phosphate = M

M = 115 g/mol

Percentage of an element in a compound:

$\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of element}}\times 100$

Percentage of nitrogen:

$\frac{1\times 28 g/mol}{115 g/mol}\times 100=24.34\%$

Percentage of phosphorus:

$\frac{1\times 31g/mol}{115 g/mol}\times 100=26.95\%$

b) Percentage of ammonia in 1 molecule of ammonium dihydrogen phosphate.

Molar mass of ammonia = 17 g/mol

$\%=\frac{17 g/mol}{115 g/mol}\times 100=14.78\%$

Amount of ammonia in 100 grams of compound:

14.78% of 100 g of ammonium dihydrogen phosphate:

$\frac{14.78}{100}\times 100 g=14.78 g$

14.78 grams ammonia is incorporated into 100. g of compound.

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3 years ago

2. Differentiate the types of tectonic plates.

kramer

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What is the total number of Joules of heat absorbed by 65.0 grams of water when the temperature of the water is raised from 25°C

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Answer:

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Explanation:

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Read 2 more answers

a compound has 15.39 g of gold for every 2.77 g of chlorine. simplified there is _____ g of gold for every 1 g of chlorine

iren [92.7K]

Answer:

There is 5.56 g of gold for every 1 g of chlorine

Explanation:

The ratio is the relationship between two numbers, defined as the ratio of one number to the other. So, the ratio between two numbers a and b is the fraction $\frac{a}{b}$

You know that a compound has 15.39 g of gold for every 2.77 g of chlorine. This can be expressed by the ratio:

$\frac{15.39 g of gold}{2.77 g of chlorine}$

The proportion is the equal relationship that exists between two reasons and is represented by: $\frac{a}{b}=\frac{c}{d}$

This reads a is a b as c is a d.

To calculate the amount of gold per 1 g of chlorine, the following proportion is expressed:

$\frac{15.39 g of gold}{2.77 g of chlorine}=\frac{mass of gold}{1 g of chlorine}$

Solving for the mass of gold gives:

$mass of gold=1 g of chlorine*\frac{15.39 g of gold}{2.77 g of chlorine}$

mass of gold= 5.56 grams

So, <u><em>there is 5.56 g of gold for every 1 g of chlorine</em></u>

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2 years ago