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Natali [406]
2 years ago
5

If 0.400 moles CO and 0.400 moles O2 completely react how many grams of CO2 are produces?

Chemistry
1 answer:
True [87]2 years ago
7 0

If 0.400 moles CO and 0.400 moles O2 completely react, 17.604 grams of CO2 would be produced.

First, let us look at the balanced equation of reaction:

2CO + O_2 ---> 2CO_2

According to the equation, the mole ratio of CO and O2 is 2:1. But in reality, the mole ratio supplied is 1:1. Thus, CO is the limiting reactant while O2 is in excess.

Also from the equation, the ratio of CO consumed to that of CO2 produced is 1:1. Thus, 0.400 moles of CO2 would also be produced from 0.400 moles of CO.

Recall that: mole = mass/molar mass

Therefore, the mass in grams of CO2 that would be produced from 0.400 moles can be calculated as:

    Mass = mole x molar mass

                 = 0.400 x 44.01

                       = 17.604 grams

More on calculating mass from number of moles can be found here: brainly.com/question/12513822

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Answer:

n a chemical reaction, delta H represents the sum of the heats of formation, commonly measured in kilojoules per mol (kJ/mol), of the products minus the sum of those of the reactants. The letter H in this form is equal to a thermodynamic quantity called enthalpy, representing the total heat content of a system.

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<h3>Answer:</h3>

A saturated solution is a chemical solution containing the maximum concentration of a solute dissolved in the solvent.

<h3>Explanation:</h3>
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3 years ago
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The correct option is: <u>B. 366 torr</u>

Explanation:

Given: <u>On the ground</u>- Initial Volume: V₁ = 8.00 m³, Initial Atmospheric Pressure: P₁= 768 torr;

<u>At 4200 m height</u>- Final Volume: V₂ = 16.80 m³, Final Atmospheric Pressure: P₂ = ?

Amount of gas: n, and Temperature: T = constant

<u>According to the Boyle's Law</u>, for a given amount of gas at constant temperature:         P₁ V₁ = P₂ V₂

⇒  P₂ = P₁ V₁ ÷ V₂

⇒  P₂ = [(768 torr) × (8.00 m³)] ÷ (16.80 m³)

⇒  P₂ = 365.71 torr ≈ 366 torr

<u>Therefore, the final air pressure at 4200 m height: P₂ = 366 torr.</u>

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