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Nostrana [21]
3 years ago
6

If a pitch from a moving vehicle sounds lower to a hearer, where is the vehicle in relation to the hearer? past the hearer befor

e the hearer above the level of the hearer’s ear below the level of the hearer’s ear
Physics
2 answers:
liberstina [14]3 years ago
6 0
I think the vehicle relation to the hearer is : Past the hearer

Have you ever walk when a motor cycle run past you ? You will notice that you will hear less sound as the motor cycle goes further

Hope this helps
Lerok [7]3 years ago
5 0

Answer: past the hearer

Explanation:

Pitch is related to frequency. Higher the frequency, higher would be the pitch. <u>From Doppler's effect</u>, we understand that there is apparent change in the frequency heard by the listener from the one emitted by the source. The apparent frequency is higher when the source and listener approach and is lower when they are moving apart.

Thus, when the pitch of a vehicle sounds lower, it means the vehicle is moving away from the hearer. It must have moved past the hearer.

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vagabundo [1.1K]

Hi there!

In this instance, the centripetal force experienced by the moon is equivalent to the gravitational force.

Thus:
\large\boxed{F_c = F_g}

Centripetal acceleration, according to Newton's Second Law:


\Sigma F = ma \\\\F_c = m * a_c\\\\a_c = \frac{F_c}{m}

Therefore:

a_c = \frac{F_g}{m_m} = \frac{2 * 10^{21}N}{1 * 10^{20}kg} = \boxed{20 N/kg}

6 0
2 years ago
Which of the following is represented by the letter A in the diagram below?
Kruka [31]

We have that the letter A in the diagram below given as

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Option A

<h3>Amplitude</h3>

Question Parameters:

Amplitude

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brainly.com/question/989117

6 0
2 years ago
For general projectile motion, when the projectile is at the highest point of its trajectory, its acceleration is zero? A)The ho
Daniel [21]

Answer:

B) Its velocity is perpendicular to the acceleration.

Explanation:

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4 0
3 years ago
Between the continental shelf and a continental rise?
Alla [95]

Answer:

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Explanation:

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8 0
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A block is launched up a frictionless 40° slope with an initial speed v and reaches a maximum vertical height h. The same block
Strike441 [17]

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Another approach to look at it this is seeing it when the Block moves up the slope, its kinetic energy decreases and the potential energy increases. In both cases, the kinetic energy decreases by same amount, therefore the block rises to same height H.

Try to use the formula;

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Where V = √(2gh)

I hope this helps

3 0
3 years ago
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